Given the optical density of a sample culture how would you determine the CFU/ml without doing a standard plate count?
1 OD of Ecoli has around 1*109 cell per ml.
So we have E.coli cell and we know the OD then we can approximately calculate the number of cells present in the culture.
For other bacteria, we need to find the cells per OD and then we can use it to calculate to the number of cells.
Please write to me if you need more help.
Given the optical density of a sample culture how would you determine the CFU/ml without doing a standard plate count?
A standard plate count of a culture of E. Coli has 175 colonies on the plate labeled 10^-6 what is the original cell density (OCD, in CFU/ml) of the original culture?
By total count you determine that the concentration of an organism in a liquid culture is 5.6 x 107 CFU/ml and you have 1 ml of this culture. Assuming that total count equals viable count, design a practical dilution and plating scheme which will result in the formation of 280 colonies per plate. Include all steps and indicate volumes and dilutions.
c)You have 0.6 mL an undiluted culture at a density of 3.7 x 107 CFU/mL. You add 5.4 mL of sterile diluent. What is the dilution and final cell density? e) Plating 2.0 mL of a sample diluted by a factor or 10-2 procedures 56 colonies. What was the original cell density in the sample? f)Plating 0.2 mL of a sample diluted by a factor or 10-4 procedures 87 colonies. What was the original cell density in the sample?
The original cell density in a sample is 4.6 x 109 CFU/mL. Which sample volume would yield a countable plate? (Express your answer as 10-x mL)
You are presented with the following results for a Standard Plate Count (SPC). What was the original starting concentration of the culture? 462 CFU 326 CFU 281 CFU 24 CFU 641 CFU 10-1 102 103 104 105
.Viable plate count Using the formula: cfu/ml = (no. of colonies x dilution factor) / volume of culture plate In plate 10-4 there were 150 colonies counted. Experimental process: Pipet 0.25 mL of the S. cerevisiae solution into the test tube labeled 10-1. Pipet the solution up and down several times to ensure all organisms are rinsed from the pipet into the test tube. Pipet 0.25 mL of the 10-1 S. cerevisiae solution into the test tube labeled 10-2. Pipet...
Count the number of CFU from each of the plates (record TNTC if there are too many to count). Record your counts below and calculate the total number of bacteria per mL and the number of ampicillin-resistant bacteria per mL in the chicken fluid. Show all your calculations in a neat logical manner in the workspace on page 4. Plate Count Plates Without Ampicillin Dilution CFU/Plate Plate # 1 Plate # 2 Average/Plate CFU/mL of Fluid 10-4 52 80 66...
(A) You have a sample with an original concentration of 1.0 x 10^7 CFU/mL. With the Plate Count Method, what final dilution factor would be needed to produce countable plates? Show your work. (B) Describe a dilution scheme (how many tubes, what volume in each tube, what DF is achieved in each step) that uses only the 9-mL blank diluent tubes to achieve the dilution needed for this FDF.
you are given three stock cultures- E coli at a concentration of 1.5 x 10^3 cfu/ml, Bacillus at a concentration of 4.2 x10^3 cfu/ml, and staphylococcus at a concentratino of 2.4 x10^4 cful/ml. you ahve been asked to make a 30 ml of a single mixed culture with a final concentration of 500 cfu/ml of E coli, 150 cfu/ml of bacillus, and 80 cfu/ml of Staph. How would you make this mixture?
please help me understand step by step how to figure out these problems. Equation 3: CFU/mL = number of colonies/mL plated TDF of the culture used for plating For example, consider the sketch below. Using the information in the figure, the plate with 50 colonies would be chosen. 1.0 mL 1.0 mL 1.0 L 1.0 mL 1.0 mL A 0.1 ml de 2.0m00m 100 m 9.0 ml 9.0 ml 9.0 mi 9.9 ml 9.0 ml Original culture 1.0 ml 2.0...