Given the information below, what is the probability that the critical path will be completed in 25 weeks?
Time Estimates (Weeks) | ||||
Activity | Optimistic | Most Likely | Pessimistic | IP |
A | 1 | 4 | 7 | None |
B | 5 | 6 | 7 | None |
C | 2 | 4 | 6 | B |
D | 4 | 16 | 10 | A |
E | 4 | 6 | 14 | A, C |
F | 6 | 8 | 16 | B |
G | 1 | 5 | 9 | D,E,F |
The probability is less than 0.25.
The probability is between 0.5 to 0.75.
The probability is between 0.25 5o 0.5.
The probability is more than 0.75.
The calculated values for expected duration, start, stop is shown below.
Activity | Optimistic | Most Likely | Pessimistic | IP | Exp | Var | Start | Finish |
A | 1 | 4 | 7 | None | 4 | 1 | 0 | 4 |
B | 5 | 6 | 7 | None | 6 | 0.111111 | 0 | 6 |
C | 2 | 4 | 6 | B | 4 | 0.444444 | 6 | 10 |
D | 4 | 16 | 10 | A | 13 | 1 | 4 | 17 |
E | 4 | 6 | 14 | A, C | 7 | 2.777778 | 10 | 17 |
F | 6 | 8 | 16 | B | 9 | 2.777778 | 6 | 15 |
G | 1 | 5 | 9 | D,E,F | 5 | 1.777778 | 17 | 22 |
The expected project duration is 22 weeks. However there are two critical paths. They have standard deviation of
ADG = 1.94 weeks
BCEG = 2.26 weeks
Using this, the z value for each of the paths are
(25-22)/1.94 = 1.54
(25-22)/2.26 = 1.32
This means their corresponding probabilities are
P(z = 1.54) = 0.9386
P(z= 1.32) = 0.9077
This makes the project completion probability about 90% or higher. This means the correct answer will be
The probability is more than 0.75
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