Question
i need to know how this was done.
Researchers cross a com plant that is pure-breeding for the dominant traits colored aleurone (C1), full kernel (Sh), and waxy
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer C: The chi-square value is 10.649. P value is below 0.01, which indicates tht the difference between the expected and obsered result is highly statistically significant

There are three People value for the significance

0.01

0.05

And 0.1

Add a comment
Know the answer?
Add Answer to:
i need to know how this was done. Researchers cross a com plant that is pure-breeding...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Mastering Genetics

    Researchers cross a corn plant that is pure-breeding for the dominant traits colored aleurone (C1), full kernel (Sh), and waxy endosperm (Wx) to a pure-breeding plantwith the recessive traits colorless aleurone (c1), shrunken kernel (sh), and starchy (wx). The resulting {rm F}_{1} plants were crossed to pure-breeding colorless,shrunken, starchy plants. Counting kernels from about 30 ears of corn, the results are reported in the table.Kernel Phenotype NumberColored, shrunken, starchy 116Colored, full, starchy 601Colored, full, waxy 2538Colored, shrunken, waxy 4Colorless, shrunken...

  • it should be something like this. please i need a detailed explaintion on the answers to...

    it should be something like this. please i need a detailed explaintion on the answers to understand whats going on.thanks In com, colored aleurone (R) is dominato colorless and green plant color is dan to yellow ( Two plants, each heterozygous for both characteristics are bestowed to honor gous recessives, and their progey are combined to produce the following boats colored green 100 colored yellow 97 colorless green 103 colorless yellow 100 Urechquare analysis to test these data for independent...

  • My degree of freedom is 0.18 but I don't know the p value nor the conclusion....

    My degree of freedom is 0.18 but I don't know the p value nor the conclusion. I have the chi square distribution for the p value below but I'm very confused on what any of this means 10 In Data Table 2, record whether your calculated p-value was greater than (>) or less than (=) 0.05. Using the p-value of 0.05 as a benchmark, determine if there was a statistically significant difference in the expected and observed results. (Refer to...

  • 5 Mailings Review View Help Design Layout Search Experimental design and procedures: 1. Use the picture...

    5 Mailings Review View Help Design Layout Search Experimental design and procedures: 1. Use the picture provided to count the number of yellow and purple corn kernels. You should count ALL of the kernels visible in the picture. Each kernel is a seed-seeds are baby plants. Therefore, each kernel represents an offspring of the plant cross. Enter these observed Values into Table 1. Page 6 3 f BE 2. Tally the total number of offspring that are yellow and purple...

  • 1. Use the picture provided to count the number of yellow and purple corn kernels. You...

    1. Use the picture provided to count the number of yellow and purple corn kernels. You should count ALL of the kernels visible in the picture. Each kernel is a seed-seeds are baby plants. Therefore, each kernel represents an offspring of the plant cross. Enter these Observed Values into Table 1. 048 2. Tally the total number of offspring that are yellow and purple by adding them together. This is the total Observed (O) value. Fill into Table 2. Table...

  • In a flowering plant, red flowers are dominant over white flowers, and short plants are dominant...

    In a flowering plant, red flowers are dominant over white flowers, and short plants are dominant over tall plants. A short plant with red flowers was self-fertilized and the phenotypes for the resulting progeny recorded (see below). Based on the observed numbers, you propose the hypothesis that this dihybrid cross follows a 9:3:3:1 phenotypic ratio, whereby Mendel's laws apply. Based on this hypothesis, you calculated the expected number of progeny for each phenotype (see below). Phenotype Observed Number of Plants...

  • HELLO, PLEASE HELP WITH QUESTIONS 8-10 PLEASE PLEASE AND THANK YOU!! PLEASE, I DON'T HAVE ANY...

    HELLO, PLEASE HELP WITH QUESTIONS 8-10 PLEASE PLEASE AND THANK YOU!! PLEASE, I DON'T HAVE ANY MORE QUESTIONS, AND I ASKED THIS 2 TIMES ALREADY AND NO RESPONSE. THANK YOU!!! APPRECIATE IT!! Question Completion Status: BUTTON Questions 5 to 11 are based on the following scenario Question 5: Although the following scenario is hypothetical, it is based on actual facts. African leopards live in a variety of habitats including forests, mountains, grasslands and deserts. Most leopards are light brown with...

  • Part 3: Identify Associations Using Real Data (where the associations are not 100%) When researchers scan...

    Part 3: Identify Associations Using Real Data (where the associations are not 100%) When researchers scan the genome using thousands of markers to identify variations that are associated with particular phenotypes, they need techniques to evaluate the strength of the associations so that they know which SNPs are closest to the locations of the genes of interest. You will do a short exercise to help you understand how this is done, followed by a chi-square test on one of the...

  • I need help with questions 1 through 2, thank you! The Esatina salamanders (Ensatina eschscholtzii), shown...

    I need help with questions 1 through 2, thank you! The Esatina salamanders (Ensatina eschscholtzii), shown above, live along the West Coast of North America from Vancouver to Baja California. We will be focusing two populations: 1. individuals that live in Northern California and represent a more ancestral population 2. individuals that live in Southern California. Researchers have found that these all individuals of this salamander species have two color phenotype, either red or blotchy. Genetic analysis has shown that...

  • Practice questions for BIO 340 (Exam 2) I need help with these questions Please. WILL GIVE...

    Practice questions for BIO 340 (Exam 2) I need help with these questions Please. WILL GIVE GOOD RATING 1. Wild type blue-eyed mary has blue flowers. Two genes control the pathway that makes the blue pigment: The product of gene W turns a white precursor into magenta pigment. The product of gene M turns the magenta pigment into blue pigment. Each gene has a recessive loss-of-function allele: w and m, respectively. A double heterozygote (Ww Mm) is self-pollinated. What proportion...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT