Johnson's rule minimizes the time to complete al jobs in both processes/ work centers.
As per Johnson's rule,
- List the Operation times for all jobs
- Select the shortest operating time (SOT) overall
- If SOT is for : 1st Process then schedule that job first OR 2nd Process then schedule that job last
- Repeat above steps until all jobs are scheduled
Looking at processing time given for all jobs in Process 1 and Process 2, we can use above logic to sequence the jobs that minimizes the flow time.
Since shortest time of 5 hours is for Job E in Process 1 hence we start with Job E. Then next shortest time of 6 hours is for Job C in Process 2, hence we will end with Job C and so on.
E -> B -> D -> A -> C
Hence, the Job A would complete processing on operation 2 at 47 hour.
So, option B. hour 47 is the correct answer.
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