Question

Drosophila Genetic Mapping

+++
98
abc
99
++c
257
a+c
217
ab+
264
+b+
214
a++
484
+bc
477

The data set tabulated above presents the results of a testcross using female flies heterozygous for three traits and male flies, which are homozygous recessive. For simplicity, mutant alleles are shown with letters a, b, and c, and wildtype alleles are indicated by a “+” symbol.


Determine the gene order (which gene is in the middle?)


Construct a genetic map for the three genes, including the map distances between them. Clearly indicate the logic you followed and show all your calculations. Include the full distance calculations for the two most distanced genes (do not just add the other 2 distances)

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Answer #1

Steps to get map distance and order between three genes are called three point mapping.The steps are,

  • Identify parental genotypes.
  • Find out the gene order.
  • Calculate map distance between the given genes.
  • Draw a genetic map including the given genes.

a++ - parental(NO) - 484
+bc - parental(NO) - 477

+++ - DCO - 98
abc - DCO - 99
They are produced when two cross-overs occur.

++c - SCO - 257
ab+ - SCO - 264
They are produced when cross-over between genes a and b occurs.

a+c -SCO - 217
+b+ - SCO - 214
They are produced when cross-over between genes b and c occurs.

When comparing the parental and DCOs,we can conclude that gene a will be situated between the two genes b and c.

Gene order will be bac or cab.




Map distance or recombination frequency between genes b and a
= SCOs produced between genes a and b + DCOs/total offsprings *100
=257 + 264 +99 +98/2110 *100 = 34cM or 34mu.

Map distance or recombination frequency between genes a and c
= SCOs produced between genes b and c + DCOs/total offsprings *100
=217 + 214 +99 +98/2110 *100 = 29.7cM or 29.7mu.

Map distance or recombination frequency between genes b and c
= 257 + 264 + 217 + 214 /2110 * 100 = 45cM.




Ans:
When comparing the parental and DCOs,we can conclude that gene a will be situated between the two genes b and c.

Gene order will be bac or cab.

Map distance or recombination frequency between genes b and a
= SCOs produced between genes a and b + DCOs/total offsprings *100
=257 + 264 +99 +98/2110 *100 = 34cM or 34mu.

Map distance or recombination frequency between genes a and c
= SCOs produced between genes b and c + DCOs/total offsprings *100
=217 + 214 +99 +98/2110 *100 = 29.7cM or 29.7mu.

Map distance or recombination frequency between genes b and c
= 257 + 264 + 217 + 214 /2110 * 100 = 45cM.
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