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When a 120 mg IV-Bolus of Drug A is administered to a patient, an AUC -60 mg/L/hr is observed. Knowing that Drug A has an hal
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Answer #1

Formula to calculate volume of distribution , Vd :

Vd = CL/KE, where CL is the clearance and KE is the elimination rate constant.

The given values are

D (dose) =120 mg

AUC (Area under curve) = 60 mg / L/hr

T1/2 ( half life ) = 12 hrs.

In(2) = 0.693 ( constant value)

Formula to calculate CL and KE

CL = D÷AUC = 120÷60 = 2

KE = In (2) ÷ t1/2 = 0.693÷12= 0.057

Vd = CL÷KE = 2÷0.057= 35 litres.

So the volume of distribution of drug A is 35 litres.

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