Question

an object have been thrown vertically into the air with an initial velocity of 6 m/sec.

a) how high will the object go?

b) how much time will the object remain in the air before it comes back to the same place?

An object has been thrown vertically into the air with an initial velocity of omso A) How high will the object go? B) How much time will the object remain in the air before it comes back to the same place? Vo = 6 m/sec hmar voor 29 219.80 = 1.83m totala voce I a.el612 sec

Answer 1

(A) qu 19 since, object is thrown vertically, velocity in y-direction My = u = 6mis. acceleration in y-direction : a = -9 [as gravity acts a = -9.8 m/s² downward or in negative y direction, at highest point, y-direction velocity : Vy = omis. So, wing v²= u² teas in y-direction, Where, & maximum Vy2= wy2-293 36 2x9.8 mase height. [ 8 = 4.837 m.] B) Total time in ain: T= 2x ( time it took to reach highest) point IT = 2xt wing v=urat in y-direction for time to reach highest point : t = vy- uy & t= 0-6 s. - 9.8 So, Total time in air: T= 2x 6 s. T= 1.22 S. Antwer