Question

The following is a fragment of double stranded DNA . The bottom strand is the template strand. It encodes a hypothetical 6 amino protein & includes the start (initiator) codon, a small amount of 5’ UTR, and a small amount of 3’ UTR

TTGGCAATGTGATCCCTTGTGCGGTACCACT

AACCGTTACACTAGGGAACACGCCATGGTGA (Template strand)

The bottom strand is the template strand and the RNA polymerase will always move from right-to-left, this is the direction of RNA synthesis

RNA transcript compares to the non-template strand by being exactly identical

The bottom strand is the template, and the RNA polymerase moves along the bottom (template) strand from RIGHTto LEFT.

a) Determine the orientation of the DNA template. The template strand is copied below. (Enter either 5' or 3' in the box below; be sure to include the apostrophe)

- A A C C G T T A C A C T A G G G A A C A C G C C A T G G T G A -

answer:?

b) In the text box below, write out the sequence and orientation of the RNA that is transcribed from this template. Identify the 5' and 3' ends, and start with the 5' end. (Format your answer exactly as follows: 5'-xxxxx.........xxxxxx-3' Be sure to include the apostrophes and the dashes before and after the actual sequence; NO SPACES).

answer:?

c) Now, use the genetic code to determine the amino acid sequence encoded by this mRNA. Counting from the N-terminus, amino acid #3 is , and amino acid # 5 is (Enter the three-letter abbreviation for each amino acid

answer:?

Answer 1

5' TTGGCAATGTGATCCCTTGTGCGGTACCACT 3' (coding/sense strand)

3' AACCGTTACACTAGGGAACACGCCATGGTGA 5' (Template strand)

The sequence of the transcript is as follows

5' UUGGCAAUGUGAUCCCUUGUGCGGUACCACU 3'

Leader

AUG- Met

UCC- Ser

This mRNA cannot be traslated into a peptide because the second codon is a ermination codon (UGA)