Homework Answers
a) The Current Capacity of the entire process is 5 unit /hr . As the operation D can produce 5unit in and hr.
Operation A , Operation B, Operation C and operation D , E , F are differente series and is parallel activity that can simultaneously process , though in and hour Operation D will process only 5 unit which can be completed in hour .
b ) Throughput time is the time taken by a unit to complete the process and The Operation A,B ,C and Operation D, E, F can work simultaneously because of parallel activity , the time taken to complete all activity upto point of Operation G will be Consider
| Unit per hour | Time for One unit | ||
| Operation A | 15unit /hour | 1hr ×60 min /15 unit per hr | 4 minute per unit |
| Operation B | 12unit/hr | 60/12 | 5 min |
| Operation C | 20/hr | 60/20 | 3 Min |
| Operation D | 5/hr | 60/5 | 12min |
| Operation E | 8/Hr | 60/8 | 7.5min |
| Operation F | 12/hr | 60/12 | 5 min |
| Operation G | 30/hr | 60/30 | 2 min |
|
Operatio H |
25/hr | 60/25 | 2.4 min |
Total time take for Series of operation A B C = 4+5 +3=12 min
And Operation D - E - F = 12+ 7.5+ 5= 25.5
Hence Thoroughput Time to complete the process = 25.5 +2+2.4 = 28.9 min or 0.48 hours
c) As the series operation of A - B - C ,the operation B which can process max unit per hour is 12 unit , Hence the parallel series of operation D and E to be increase to 12 unit per hour, so
| Operation Capacity to increase | Capacity increase by |
| Operation D | 12-5= 7 unit |
| Operation E | 12-8= 4 Unit |
Hence after increase in operation capacity of D and E the entire process capacity will be 12 unit per hour .
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