Question

A portion of DNA sequence is    5’ ATCGCGCTCAGCTAGTACCGATCAGCAGTCAGCAGTCAGCATCGGT 3’ (top)    3’ TAGCGCGAGTCGATCATGGCTAGTCGTCAGTCGTCAGTCGTAGCCA 5’ (bottom)...

A portion of DNA sequence is

   5’ ATCGCGCTCAGCTAGTACCGATCAGCAGTCAGCAGTCAGCATCGGT 3’ (top)
   3’ TAGCGCGAGTCGATCATGGCTAGTCGTCAGTCGTCAGTCGTAGCCA 5’ (bottom)

Assume GTACCGATCAGCAGTCA and CATGGCTAGTCGTCAGT are introns

1) Which strand will be the template strand for the transcription?

2) Write down the mature messenger RNA sequence, label the 5' and 3' ends, and additional elements found in mature messenger RNA.

3) Based on the mRNA sequence, draw a line between each codon in question 2) and write the sequence for the polypeptide that can be translated from the N-terminus to C-terminus.

4) If Cas9 used an eight bp long guide RNA sequence, which of the following two sequences would be, assuming that Cas9 cuts the DNA down the middle of the guide RNA sequence?

#1: 5’ACCGAUCA 3’ #2: 5’ATCGCGCT 3’

0 0
Add a comment Improve this question Transcribed image text
Answer #1

5’ ATCGCGCTCAGCTAGTACCGATCAGCAGTCAGCAGTCAGCATCGGT 3’ (top)
3’ TAGCGCGAGTCGATCATGGCTAGTCGTCAGTCGTCAGTCGTAGCCA 5’ (bottom)

Coloured region shows the intron.

1)  5’ ATCGCGCTCAGCTAGTACCGATCAGCAGTCAGCAGTCAGCATCGGT 3’ (top) - Coding strand
3’ TAGCGCGAGTCGATCATGGCTAGTCGTCAGTCGTCAGTCGTAGCCA 5’ (bottom) -Template strand

2) mRNA will be transcribed from template strand -

3’ TAGCGCGAGTCGATCATGGCTAGTCGTCAGTCGTCAGTCGTAGCCA 5’ (bottom) -Template strand

5' AUCGCGCUCAGCUAGUACCGAUCAGCAGUCAGCAGUCAGCAUCGGU 3'- pre- mRNA

Exon Intron Exon     

Intron region will be removed by the splicing and exons combine to form the mature mRNA -

5' AUCGCGCUCAGCUAGCAGUCAGCAUCGGU 3' - Mature mRNA .

3) 5' AUC GCG CUC AGC UAG CAG UCA GCA UCG GU 3'

N terminus - Ile- Ala-Leu-Ser-stop-Gln-Ser-Ala-Ser. (Polypeptide sequence).

4) #1 5’ACCGAUCA 3’ would be correct answer , assuming that Cas9 cuts the DNA down the middle of the guide RNA sequence, because it binds in the intron middle region.

5' AUCGCGCUCAGCUAGUACCGAUCAGCAGUCAGCAGUCAGCAUCGGU 3'- pre- mRNA

#2: 5’ATCGCGCT 3’ binds in exon region -

5’ ATCGCGCTCAGCTAGTACCGATCAGCAGTCAGCAGTCAGCATCGGT 3’ (top) - Coding strand

Add a comment
Know the answer?
Add Answer to:
A portion of DNA sequence is    5’ ATCGCGCTCAGCTAGTACCGATCAGCAGTCAGCAGTCAGCATCGGT 3’ (top)    3’ TAGCGCGAGTCGATCATGGCTAGTCGTCAGTCGTCAGTCGTAGCCA 5’ (bottom)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Below is a portion of DNA sequence, introns are shown in bold. Determine which strand contains...

    Below is a portion of DNA sequence, introns are shown in bold. Determine which strand contains a start codon and could serve as the template for synthesis of an mRNA molecule. 5’ ATCGCGCTCAGCTAGTACCGATCAGCAGTCAGCAGTCAGCATCGGT 3’ (top) 3’ TAGCGCGAGTCGATCATGGCTAGTCGTCAGTCGTCAGTCGTAGCCA 5’ (bottom) a. Which strand will serve as the template strand for transcription? b. Based on the template strand you have chosen, write the mature mRNA sequence on your answer sheet in the 5’ to 3’ direction. Be sure to label 5’ and...

  • 11. Using the DNA sequence below and the codon table on the projector, perform the following:...

    11. Using the DNA sequence below and the codon table on the projector, perform the following: a. Produce the correct MRNA transcript. On the DNA sequence below, the top strand is the template strand, and transcription begins immediately following the promoter sequence and ends at the end of the DNA sequence. (5 points) b. Produce the correct polypeptide sequence. (5 points) Prometer GTCACGGGTACCCTGTGTTAAGGCATCGTATGATACATACCACTATGTACCATGGACACAATTCCGTAGCATAAGCATGACCC CAGTGCCCATGGGACACAATTCCGTAGCATACTATGTATGGTGATACATGGTACCTGTGTTAAGGCATCGTATTCGTACTGGG 11. Using the DNA sequence below and the codon table on the projector, perform the following:...

  • 3. The partial gene (DNA) sequence below contains multiple PAM sequences. Highlight six PAM sequences in...

    3. The partial gene (DNA) sequence below contains multiple PAM sequences. Highlight six PAM sequences in the top (5' to 3) strand. 5'-GCACGGCGGAGCGGTTCTTGGCAGCGGCCGCACGATCTCGTTGCCGCCGG- 3' 3-CGTGCCGCCTCGCCAAGAACCGTCGCCGGCGTGCTAGAGCAACGGCGGCC- 5' Once Cas9 binds to a PAM sequence, it unwinds the DNA. If the guide RNA matches the DNA sequence next to the PAM, the guide RNA will bind to the complementary DNA strand. If not, the DNA will zip back together and Cas9 will keep binding to other PAM sequences until it finds the...

  • A segment of a double-stranded DNA molecule is shown below. The start of a gene is...

    A segment of a double-stranded DNA molecule is shown below. The start of a gene is indicated as the +1 base pair: + 1 5'TATATTTTCTATATGCACATTTGCAAGTAA 3'(strand A) 3'ATATAAAAGATATACGTGTAAACGTTCATT 5'(strand B) Uparrow (A) If RNA polymerase moves along this DNA from left to right, indicate the position of the promoter region on this DNA and indicate which strand is the template strand (B) Write the complete mRNA that would be transcribed from the gene above, again being sure to label the...

  • Fill in the complementary base pairs for the strand below STACGCCCATTI TAGA ATTGCGTGGGCATTAAGTTTTA TACC3 DNA sequences...

    Fill in the complementary base pairs for the strand below STACGCCCATTI TAGA ATTGCGTGGGCATTAAGTTTTA TACC3 DNA sequences 3' I Find and put a square around the TATA box (promoter) in the double stranded DNA above Find and circle the terminator sequence (GGGCG) in one of the strands above The strand with promoter and terminator is the strand of interest: using the template strand, synthesize an mRNA sequence mRNA molecule in the boxes below; pay attention to polarity 53: Find and circle...

  • Below are several DNA sequences that are mutated compared with the wild-type sequence: 3-TAC TGACTGACGAT C-5....

    Below are several DNA sequences that are mutated compared with the wild-type sequence: 3-TAC TGACTGACGAT C-5. Envision that each is a section of a DNA molecule that has separated in preparation for transcription, so you are only seeing the template strand. Construct the complementary DNA sequences (indicating 5' and 3' ends) for each mutated DNA sequence, then transcribe (indicating 5' and 3' ends) the template strands, and translate the mRNA molecules using the genetic code, recording the resulting amino acid...

  • Given the template DNA sequence below: 3'-CCACCTTCTATACTTCGCGGAATGCCGGTCCATGTAGGTTCACATTAGCGT-5' 6. An error occurred in DNA replication, A was...

    Given the template DNA sequence below: 3'-CCACCTTCTATACTTCGCGGAATGCCGGTCCATGTAGGTTCACATTAGCGT-5' 6. An error occurred in DNA replication, A was incorporated in the place of T (indicated in yellow color in the aforementioned sequence) from the gene. Write the corresponding DNA template strand and transcribe the mutated mRNA strand, then determine the amino acid sequence of the mutant protein. If a stop codon is not present, create one by adding sequences to the gene and mRNA.

  • 3. Now consider the sequence that results for a different mutant protein. Using the DNA coding...

    3. Now consider the sequence that results for a different mutant protein. Using the DNA coding strand sequence provided, predict the sequences of the DNA template strand, mRNA, and polypeptide for the mutant gene. DNA coding strand for mutant gene 2: S'ACTGCCCLATGGTGTAG CTG ACTCCTGAGGAG13 On the line above, write the sequence for the template DNA strand, On the line below, write the sequence for the mRNA for mutant protein: On the line below, write the sequence for the Polypeptide for...

  • A portion of the template strand of DNA has the following sequence: 5' ATA GCG TTC...

    A portion of the template strand of DNA has the following sequence: 5' ATA GCG TTC CAC CGC 3'. Assume the first codon for the peptide begins with the first nucleotide of the portion of mRNA and there are no introns (May not start at AUG). Enter the mRNA and amino acid sequence below

  • 4. Now consider the sequence that results for a different mutant protein. Using the DNA coding...

    4. Now consider the sequence that results for a different mutant protein. Using the DNA coding and sequence provided, predict the sequences of the DNA template strand, mRNA, and polypeptide for the mutant gene. DNA coding strand for mutant gene 3: 5'ACTGCCCATGGTGGTACCT GAC TCC TGAGGAG 3' On the line above, write the sequence for the template DNA strand. On the line below, write the sequence for the mRNA for mutant protein: On the line below, write the sequence for the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT