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Please solve all these questions and give a detailed explanation for your answer. When drawing the bode plots, please make sure that they are hand drawn. Please show in detail how you got them and hopefully all your answers are correct. When drawing the bode plots for the magnitude, the y-axis should be 20log(abs(H(jw))). When drawing the bode plots for the phase, the y-axis should be in degrees. The x-axis for both plots should be "w". Thank you very much for all your help in advanced.

2. Draw (by hand) the Bode plots (magnitude and phase) for each of the following transfer functions. s+10 (a) H(s) = 554192 1

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H(SI = S410 101 to sto) S(SH 5 (5412 Mljw) - j wtlo jw (j wt THLUNDI w2110 w (w²11) <H (JW) = tant (W/10) -9° -grant (w) ploHy wil do 40 7 -20 drlded! 109 -40d 1 -4old & dec) to to tradisec) - no ot deseades = 109 10 1091 How I w-10 = 20- 60L) - 40(<H(SW)= tant (600) aortan (~) w < HIGW) - 100.80 -174.29° 10 - 2/3.580 100 - 184.6° <Hljw) -aot -1204 -158 -1807 2100 - igu 2starting toeruency wool M(WW) I w=01 - 2010go 2010g10 - --- 60dB) 1 Hjul de yo 20 de deo) s logo 100 103 40 (ABldec) Onl to 1ZH LJU) = 1800 tant/w/10) - tam (w/100) <Hlja) 179 170 129° 100 103 <Hlju), 180+ 13507 90+ ugot --- T so we H(S)= 1988 (1 ooStarting Starting w=0.1 rad(ec) Hl5W) I w=0.1 = sologell) - old B) Hull do oldigt 20 (1B (dec) 40 (013) logio 1 10 102 ios 1KHLGW) 0 30 +++htts E Oo 30° + -60+ -98 1 10 102 103 104 105 Hera al (2 + 56+1) X 100 x² (5+1) He Lu) a 10 (220 + 5+1) s2 (5+preciul do 60 * culdaldee) logio - 10 -60 AB dee) 407 - 60 (dol -old Bf dee) ool to loadsec), slope = -40 dB (dee & no ot dec5 w (100-w? tem 1 <H184) = tant Low ) - 1800 _ tans (w), wat <H (SW) 2 460- tan w o) 180 - tan (60) = - tant (su oro ) - tan

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