Question

Answers (a) A = 53.8 m2, edge has length 7.34 m, (b) 50,000 V/m,

(c) 13.8 μJ
Note: For (b) I used E = σ / (κ ε0 ) and in (c) I used U = Q²/(2C)

2. Teflon-Filled Capacitor A parallel-plate capacitor is made by placing a 10 μm layer of Teflon between two aluminum sheets. The dielectric constant of Teflon is K = 2.1 . The capacitance is C= 100 μF. The capacitor is square in shape. A charge of ±5 is applied to the two plates of the capacitor. (a) What is the area of the capacitor? What is size of the square? (b) What is the electric field strength inside the capacitor? (c) Consider the capacitor described above. Suppose the charge, plate area, and plate spacing are fixed and then the Teflon layer is pulled out from in between the aluminum sheets. How much work must be done in order to pull out the Teflon sheet? Note: When the area between the plates is filled with a dielectric such as Teflon, the field and potential decrease by a factor of k and the capacitance increases by a factor of k, compared to the values with air between the plates. (x is the dielectric constant of the material between the plates.)

Answer 1

tSouc 10乂1U 2-C 55x10