Question

Part A B 0.11 T and F 3.6x10-13 N. What is the electric field strength at the position of the electron in (Figure 1)? Assume that Express your answer with the appropriate units. E- 1.9x10 Correct Part B What is the electric field direction at the position of the electron? , measured clockwise trom the positive z axis in zy plane Submit gure 1 of 1 Incorrect: One attempt remaining: Try Again Provide Feedback 30° Moving out of page at 1.0x 10' m/s

Find the angle

Answer 1

F_m^vector = -e middot v^vector - B^vector Vertical-bar F_m Vertical-bar = 1.6 times 10^-9 times 1 times 10^7 times 0.11 = 1.76 times 10^-13 N tan phi = Vertical-bar F_m^vector Vertical-bar sin 60 degrees/ Vertical-bar F^vector Vertical-bar + Vertical-bar -F_m Vertical-bar middot cos 60 tan phi = 1.76 times 10^-13 times squareroot 3/2/3.6 times 10^-3 + 1.76 times 10^-3 times 1/2 phi = 18.78 degrees theta = 30 + 18.78 degrees = 48.78 degrees