Question

Example Problem1 A 15 kg block is on a ramp which is inclined at 20° above the horizontal. It is connected by a string to a 19 kg mass which hangs over the top edge of the ramp. Assuming that frictional forces may be neglected, (a) what is the magnitude of the acceleration of the 19 kg block? (b) Find the tension of the string. 19 20°

Instructor gave 87 N for the answer for part b and I am not getting that same answer. Thanks.

Answer 1

M_ = 15 kg m_2 = 19 kg. theta = 20 degree (a) since both block are connected by a single string so acceleration of both blocks will be same. Let a be the acceleration of each block force body diagram of m_ is where N be the normal reaction on m_1 from in clirud surface. T be the tension in the \r\n from newton's second law T - m_1 g sin 20 = m_1 a force body diagram of m_2 is from newton's second law m_2 g - T = m_2 a T = m_2 g - m_2 a - - - (ii) Now we put this value in equation (i) m_2 g - m_2 a - m_1 g sin 20 = m_1 a m_2 g - m_1 g sin 20 = (m_1 + m_2) a Now we p[ut values of m_1, m_2 19 times 9.8 - 15 times 9.8 sin 20 degree = (15 = 19)a