From the given sample
Mean = 5.925
Sample standard deviation S = 0.669
95% confidence interval for is
-
t
/2 S /
sqrt(n) <
<
+
t
/2 S /
sqrt(n)
5.925 - 2.201 * 0.669 / sqrt(12) < < 5.925 + 2.201
* 0.669 / sqrt(12)
5.4999 < < 6.3501
95% CI for is
(5.4999,6.3501)
Section #13070 7) A random sample of 12 chickens is selected from a chicken processin amount...
Independent random samples were selected from two quantitative populations, with sample sizes, means, and standard deviations given below. n1 = n2 = 60 x1 = 125.3 x2 = 123.4 s1 = 5.7 s2 = 6.1 a) Construct a 95% confidence interval for the difference in the population means (μ1 − μ2). (Round your answers to two decimal places.) to b) Find a point estimate for the difference in the population means. c) Calculate the margin of error. (Round your answer...
2) In a hospital, a random sample of 12 weeks was selected, and it was found that an average sample of 537 patients were treated in the emergency room each week. The standard deviation was 21.82. Assuming that the variable is normally distributed, find the 90% confidence interval of the true mean. 90% confidence interval:
A laboratory tested 40 chicken eggs and found that the mean amount of cholesterol was 201 milligrams. It is known that the standard deviation of all such chicken eggs is s = 14.3 milligrams. Construct a 95 percent confidence interval for the true mean cholesterol content of all such eggs. O 197.3 <mu <204.7 196.6 < mu < 205.4 196.4 <mu <205.6 O 192.0 < < 210.0 Question 3 6 pts A randomly selected group of 40 bowlers from a...
An independent random sample is selected from an approximately normal population with an unknown standard deviation. a) Given the sample mean = 24.3, sample standard deviation = 8.5, and sample size = 32, compute the standard error. The standard error = b) Using a confidence coefficient of 2.04, compute the confidence interval. The 95% confidence interval goes from to (Enter the smaller number first.) c) Based on the confidence interval above, which of the following values are plausible? (Choose all...
5. The following random sample was selected from a normal distribution: 5 20 18 3 10 2 6 9 19 13 a) Construct a 90% confidence interval for the population mean μ: SHS b) Construct a 95% confidence interval for the population mean :
A sample of 81 tobacco smokers who recently completed a new smoking cessation program were asked to rate the effectiveness of the program on a scale of 1 to 10, with 10 corresponding to completely effective" and 1 corresponding to completely ineffective". The average rating was 5.6 and the Construct a 95% confidence interval for the mean score. 4.6< <6.6 O<< 5.6 5.1 <<6.1 5.2<<6.0
SECTION 7 - 2 1. A simple random sample of 39 salaries of NCAA football coaches has a mean of $416,953 with standard deviation $462,364. Construct a 95% confidence interval estimate of the mean salary of an NCAA football coach. 2. In a test of weight loss programs, 27 adults used the Atkins weight loss program. After 12 months, their mean weight loss was found to be 2.4 lb, with a standard deviation of 4.7 lb. Construct a 90% confidence...
1. A random sample of 25 observations was selected from a normally distributed population. The average in the sample was 84.6 with a variance of 400.a. Construct a 90% confidence interval for μ.b. Construct a 99% confidence interval for μ.c. Discuss why the 90% and 99% confidence intervals are different.d. What would you expect to happen to the confidence interval in part (a) if the sample size was increased? Be sure to explain your answer.
Independent random samples were selected from two binomial populations, with sample sizes and the number of successes given below. Population 1 2 500 500 120 147 Sample Size Number of Successes Construct a 95% confidence interval for the difference in the population proportions. (Use P, - Pg. Round your answers to four decimal places.) - 1087 to
Question 14 8 pts A laboratory tested a sample of 100 chicken eggs and found that the mean amount of cholesterol was 257 milligrams; the population standard deviation for alleggs is 15.2 milligrams. Use this data to construct a 95 percent confidence interval for the true mean cholesterol content of all such eggs. (251.02.262.981 1255.02.261.981 1249.02, 264.98) (254.02, 259.98) Question 15 8 pts A group of 19 randomly selected students from a state university has a mean age of 224...