Question

Experiment 1 - Bacterial Transformation Questions 1. Pill out the following table with your predictions for the bacterial transformation Imake sure to keep a copy of your predictions on a separate paper for lab next Plate # | Plate Contents week). Experiment Growth +orPresent Color lf Growth Added Plasmid E coli + Plasmid E. coli - Plasmid E. coli + Plasmid E. coli 3a LB, Amp, X-gal .Plasmid E. coli 3b LB, Amp, X-gal Plasmid E. coli 1b LB 2a LB, Amp 2b LB, Amp За 2. Describe the two genes the plasmid contains.

Answer 1

Before answering your question I am assuming that the plasmid you have used in the study is just an empty plasmid vector which does not contain any gene of interest. Therefore the plasmid has an intact Beta-galactosidase gene which can cleave the X-gal to give blue colored colonies in the agar plate.

Based on the above assumption the table is as follows:

Plate #	Plate contents	Experiment added	Growth (+ or -)	Color if growth present
1a	LB	- Plasmid E. coli	Growth +	No color (Normal White colonies)
1b	LB	+ Plasmid E. coli	Growth +	No color (Normal White colonies)
2a	LB, Amp	- Plasmid E. coli	Growth -	No colonies
2b	LB, Amp	+ Plasmid E. coli	Growth +	No color (Normal White colonies)
3a	LB, Amp, X-gal	- Plasmid E. coli	Growth -	No colonies
3b	LB, Amp, X- gal	+ Plasmid E. coli	Growth +	Blue color colonies (white color colonies if your plasmid has a gene of interest which as disrupted the Beta-galactosidase gene.)

Ans 2. The plasmid contains two genes:

1. gene for LacZ which can produce Beta-galactosidase enzyme

2. The plasmid contains the ampicillin resistance gene which helps the bacteria to grow in the presence of ampicillin.