1. (15pts) Design a LEAD controller for the heading control of an antenna. The purpose of...
please solve this problem with detail description. A simple but practical feedback control system is shown below. It is a positioning system or position servo for a large video satellite antenna modeled as a mass having a large moment of inertia, J. An output potentiometer measures the output shaft position, converting the position to a proportional voltage according to vo-Kye. where, e is the output shaft angle in radians and vo is the output potentiometer voltage; Kp is the constant...
Q.4 A position control system is shown in Figure Q4. Assume that K(s) = K, the plant 50 s(0.2s +1) transfer function is given by G(s) s02s y(t) r(t) Figure Q4: Feedback control system. (a) Design a lead compensator so that the closed-loop system satisfies the following specifications (i) The steady-state error to a unit-ramp input is less than 1/200 (ii) The unit-step response has an overshoot of less than 16% Ts +1 Hint: Compensator, Dc(s)=aTs+ 1, wm-T (18 marks)...
Problem 51: (25 points) Figure 5 is an example of a feedback control system that is designed to regulate the angular position θ(t) of a motor shaft to a desired value θr(t). The signal e(t) represents the error between the measured shaft angle θ(t) and the desired shaft angle θ (t). The Laplace transforms ofa,(t), θ(t), and e(t) are denoted as ΘR(s), θ(s), and E(s), respectively. The control gains Ki and K2 are chosen by the control engineer to achieve...
urgent! II Lead-Lag Controller Design A plant has the open-loop transfer function with unity feedback: 20(s +1) G, (s) s(10s +D(0.1258 +D(0.05s +1)(0.02s +1) Design a phase lag-lead compensator that satisfies the following specifications must by the compensated system 1. The steady-state error for a unit ramp input must be 0.002; 2. The compensated phase margin must be approximately 48; must be approximately 25 rad/sec. II Lead-Lag Controller Design A plant has the open-loop transfer function with unity feedback: 20(s...
The parameters are as follows k=10 a=0.50 b=0.3 c=0.6 d=9 w_1=12 w_2=15 Kv=30 A feedback control system (illustrated in Figure 1) needs to be designed such that the closed-loop system is asymptotically stable and such that the following design criteria are met: the gain crossover frequency wc should be between w1 and w2. the steady-state error should be zero in response to a unit step reference. the velocity constant should be greater than Kv (in other words, the steady-state unit...
G) r(t) Figure 1: Feedback control system A pulley and belt transmission has a linearized relationship between the driven pulley angle θ(t) in degrees and the input torque u(t) in Newton meters given by the following differential equation du(t) A feedback control system (illustrated in Figure 1) needs to be designed such that the closed-loop system is asymptotically stable and such that the following design criteria are met: 1. the gain crossover frequency a should be between and a 2....
The parameters are as follows k=10 a=0.50 b=0.3 c=0.6 d=9 w_1=12 w_2=15 Kv=30 A feedback control system (illustrated in Figure 1) needs to be designed such that the closed-loop system is asymptotically stable and such that the following design criteria are met: the gain crossover frequency wc should be between w1 and w2. the steady-state error should be zero in response to a unit step reference. the velocity constant should be greater than Kv (in other words, the steady-state unit...
9 T F Any control system must capable of reducing errors to some small value and the system must be stable. 10 T F Delay time is the time needed for the response to reach 0.6 final value at the very first time. 11 T F The settling time in the second order system is 4 times of time constant. 12 T F Using PD controller in the position control system with a ramp input, to reduce the steady state...
The parameters are as follows k=0.1,a=1.00,b=1,c=1.0,d=25,w_1=20,w_2=25,Kv=50 e(t) r(t) e (t) G(s) Figure 1: Feedback control system A pulley and belt transmission has a linearized relationship between the driven pulley angle e (t) in degrees and the input torque u(t) in Newton meters given by the following differential equation du(t) dt A feedback control system (illustrated in Figure 1) needs to be designed such that the closed-loop system is asymptotically stable and such that the following design criteria are met 1....
Question: CODE: >> %% PID controller design Kp = 65.2861; Ki = 146.8418; Kd = 4.0444; Gc = pid(Kp,Ki,Kd); % close-loop TF T = feedback(G*Gc,1); %% checking the design obejective a_pid = stepinfo(T); % Settling Time tp_pid = a_pid.SettlingTime % Overshhot OS_pid = a_pid.Overshoot %% steady-state error [yout_pid,tout_pid] = lsim(T,stepInput,t); % steady-state error ess_pid = stepInput(end) - yout_pid(end); >> %% Effect of P in G Kp = 65.2861; Ki = 0; Kd = 0; Gc = pid(Kp,Ki,Kd); % close-loop TF...