Question

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For a bimolecular reaction, A+B---->C, a research scientist has collected sufficient data to construct time courses. The scientist incubated reactants A and B together and observed the formation of product C with increasing reaction time. The scientist then repeated this in the presence of [A] = 15 M and varied concentrations of B (All data are provided in the attached Microsoft Excel document. The concentration of B has been varied as indicated. Data have been provided in both raw and corrected formats). Please utilize these data to answer the following questions:

a. Please clearly explain why the concentration of reactant A has been fixed at a constant, large concentration. Please answer using grammatically correct, complete sentences.
b. Please utilize the attached dataset to estimate the value of the bimolecular rate constant for the reaction of A and B. For partial credit, please show all work in a way that can be clearly understood.
c. What are the units on your estimate of the bimolecular rate constant as determined in part b of this question? How did you arrive at this conclusion? Please clearly explain your logic.

o 625 0.0206724 0.017722 Low A+B->C, Observing formation of C [A] = 15 M, [B] (M) Varied (Listed below) 11 0.9 0.81 0.71 0.6 0.5 0.4 0.3 0.21 0.1 time (s) [C] (M) 0 0 0 0 0 0 0 0 0 0 0.05 0.029525 0.0265754 0.023625 0.0206740 0.017722 0.0147704 0.0118170.0088637 0.0059097 0.002955 0.10.058124 0.052322 0.046517 0.0407109 0.0349014 0.0290904 0.0232764 0.017460 0.0116424 0.005822 0.15 0.085829 0.07726810.0687019 0.0601304 0.051555 0.042974: 0.0343891 0.025799 0.017204 0.008604 0.2 0.112671 0.1014408 0.090202 0.07895510.0677004 0.056437 0.0451664 0.033887 0.0225999 0.011303 0.250.1386791 0.124866 0.111041 0.0972034 0.083354 0.069492 0.055618 0.041732 0.027833 0.013923 0.3 0.1638820 0.1475699 0.131240 0.114895 0.098532 0.082152 0.065756 0.0493424 0.032911 0.016464 0.35 0.188307 0.169575 0.1508224 0.132047 0.1132498 0.0944301 0.075588 0.0567241 0.037838 0.0189304 0.4 0.2119808 0.1909074 0.1698064 0.148678 0.1275214 0.106337 0.0851257 0.063886 0.0426184 0.0213231 0.45 0.234928 0.211587 0.188212 0.164804 0.141362 0.117886 0.094376 0.0708334 0.047256 0.023645 0.5 0.25717410.231636 0.2060594 0.180442 0.1547850.129087 0.1033504 0.0775731 0.051755 0.0258984 0.55 0.2787414 0.2510764 0.2233654 0.1956074 0.1678037 0.139953 0.1120559 0.08411210.056121 0.028084 0.6 0.299652 0.269926 0.240148 0.210316 0.180431 0.150492 0.120501 0.090455 0.060357 0.0302059 0.65 0.3199299 0.288207 0.256424 0.2245811 0.192679 0.160716 0.128693 0.0966108 0.0644674 0.0322640 0.7 0.3395939 0.305935 0.2722104 0.2384181 0.2045601 0.170634 0.136642 0.1025824 0.0684551 0.034261 0.75 0.358663 0.323129 0.287522 0.251840 0.216085 0.180256 0.144353 0.1083761 0.072325 0.0361999 0.8 0.3771599 0.3398074 0.302374 0.264861 0.227266 0.189591 0.151835 0.113998 0.0760804 0.0380809 0.85 0.3951004 0.355985 0.3167829 0.277492 0.2381144 0.198648 0.159095 0.1194531 0.079724 0.039906 0.9 0.4125037 0.371679 0.3307604 0.2897464 0.2486387 0.207436 0.166139 0.124746 0.0832597 0.0416779 0.95 0.4293864 0.386904 0.3443204 0.3016359 0.2588499 0.215962 0.1729734 0.129883 0.0866901 0.043396 1 0.4457659 0.4016759 0.3574774 0.313171 0.2687571 0.2242357 0.1796054 0.1348670 0.0900204 0.0450644 1.05 0.4616577 0.4160074 0.370243 0.324364 0.2783714 0.232263 0.1860410 0.1397034 0.0932508 0.046683 1.1 0.477077 0.4299141 0.3826304 0.335225 0.2877002 0.2400534 0.192285 0.1443961 0.096386 0.0482539 1.15 0.4920400 0.4434088 0.3946504 0.345765 0.296752 0.2476131 0.1983460 0.148951 0.0994287 0.049778 1.2 0.506560 0.456504 0.4063151 0.3559931 0.305537 0.254949 0.2042260.153371 0.102381 0.0512571 1.25 0.520651 0.469212 0.4176354 0.365919 0.3140634 0.262068 0.209934 0.157660 0.1052461 0.052693 1.3 0.5343270 0.4815468 0.4286218 0.3755520.322337 0.268977€ 0.215473 0.161822 0.1080274 0.0540869 1.35 0.5476004 0.4935171 0.4392848 0.384901 0.3303671 0.2756834 0.2208484 0.1658627 0.110726 0.0554384 1.4 0.560484 0.5051369 0.4496341 0.3939751 0.338161 0.282191 0.2260654 0.1697834 0.113345 0.0567507 1.450.5729900 0.516415 0.459679 0.4027834 0.3457264 0.2885080 0.231128 0.1735889 0.1158864 0.058024 1.5 0.5851299 0.527363 0.469430 0.4113324 0.3530684 0.294638 0.236043 0.1772814 0.1183531 0.0592599 1.55 0.5969149 0.5379901 0.478896 0.419631 0.360195 0.300589 0.2408129 0.1808654 0.1207478 0.0604591 1.6 0.608356 0.5483074 0.488084 0.427686 0.3671139 0.306365 0.2454424 0.1843444 0.123071 0.0616231 1.65 0.6194640 0.5583240 0.4970048 0.4355064 0.373828 0.3119720 0.249936 0.1877207 0.125326 0.0627527 1.70.630248 0.5680484 0.505664 0.443097 0.3803474 0.317414 0.2542974 0.190997 0.1275149 0.0638490 1.75 0.640720 0.57748990.5140721 0.4504679 0.3866751 0.322696 0.258531 0.194178 0.129639 0.0649129 1.80.650887 0.5866568 0.5222349 0.457622 0.3928190 0.327825 0.2626407 0.197265 0.1317001 0.0659454 1.85 0.6607610 0.595557 0.530160 0.4645680.3987824 0.3328031 0.26662910.200262 0.1337011 0.066947 1.9 0.670348 0.6042001 0.5378554 0.4713127 0.404572 0.337635 0.270501 0.203171 0.1356431 0.0679200

Answer 1

to cela for a bimolecular reaction AB c. Rate expression is given as Rate = K CABECBJY Now experiment as conducted to know rate, rate constant #2 - and rate g reaction with each reactant CA) and CBJ concentrations e value of x and y. [ Expanants or order of reaction with concentration & CA and CBI reactants J. And @ Now ccrrcen trefien's ą one z the reactant Chere AJ is Kept constant and large. i As the concentration of CAS is constant ipn expression rate - KCAICBJ - 0 - K [constant) (BJ" - K CBJY no hese ka keng - New constant. - in expression ④ rate ak[B] you neet to observe rate with respect to concentration of CB] only which become's quite easy than varing concentrelico's & Both CAJ and CBS. Now, it is kept large like first order behaves Because now reaction reaction and such type of reactions are called Pseudo first order reaction's - - - 6 Now take reading frow for simplificcelinos consider o change in concentration dataset reading's C2, 3074] & Reactant oxproduct o Ra time.

a. Rate . Change in concentrahin CcJ m. S time (sec.) - increase in CCIM time. considering any three reading's Ranalom for simplification alhen time z I see a rec and 3 sec. and conc. of (B] = oll and 0.2 m C you can take any concentrations Conc time I se I rate = increase in [c] m when t=lsea 0.045064 ' 0.045064 time 1 rate = 0.45064 /sec. for conc. q B = oolm and fetes 0.0900201 sec. ar 1, rate2045064 = k'CBJ = K 0.134 any sate = 0,090020 = KCB JP = K'C0.237 from the values obtained i is clear that rate double's from 0.45064 m to 0.090020 per sec. when concentration q B doubles from o.lm to 0.2m & EAJ is constant (15m3 " It is clear that reaction is first order Wik espect to come a CB1 : у 1 and as reaction soe is bimolecular value q ki can be determined:

ease or simplification . Rate = change in concentration CcJ M. time (sec.) = increase in [c] m time. considering any three reading's Ranelom for simplification achen time = I see. 2 free and 3 sec. and conc.f CB] = oil and 0.2 m C you can take any conan S rate = increase in [c] m 0.045064 0.045064 when t-Isec time time I se: 1 rate = 0.45064 [sec. for conc. q B = oolm and rate = 0.090020/sec. B = 0.2m. c you can take any concentrations) ratez 2045064 = k'CBjkl 20.13 any fate = 0.000020 = KICBJP = k'C0.21? from the values obtained it is clear that rate double's from 0.45064m to o.o 90020 per sec. when concentration of a doubles from o.lm to 0.2m. & CAJ is constant (15mJ . A It is clear that reaction is first order with respect to cance of CB] .y=1 and as reaction ge is bimolecular value q * can be determined. As sete = K CB3' K'E BJ opply1] - for B=Oolm rate CBI K wenye oro 60045 0.45 M/s 2 0.45 / sec. K = teate, 0.090020, 0.45 1sec B=0. 2M 20.45 / sec.