1. Using the following DNA segment, the RNA transcribed and the translation
DNA 5’ ATG CCG GGT ACA TTC GGC CCA TAC 3’
DNA 3’ TAC GGC CCA TGT AAG CCG GGT ATG 5’
RNA 5’ AUG CCG GGU ACA UUC GGC CCA UAC 3’
Protein met pro gly thr phe gly pro. tyr
DRAW an example of each of the following (circle the mutation that
has occurred):
A silent mutation
A frameshift mutation
A nonsense mutation
A missense mutation
silent mutation is a point mutation that does not change the amino acid, the original codon and the mutated codon codes for the same amino acid.
the 6th nucleotide is changed from G to T
mutated DNA is :
DNA 5’ ATG CCT GGT ACA TTC GGC CCA TAC 3’
DNA 3’ TAC GGA CCA TGT AAG CCG GGT ATG 5’
mutated RNA is : 5’ AUG CCU GGU ACA UUC GGC CCA UAC 3’
amino acid sequence is: Met-Pro-Gly-Thr-Phe-Gly-Pro-Tyr
A frameshift mutation is due to the insertion or deletion of nucleotides which are not in the multiples of 3, this changes the reading frame from that point.
C at the 18 th position is deleted
new DNA sequence
DNA 5’ ATG CCG GGT ACA TTC GGC CAT AC 3’
DNA 3’ TAC GGC CCA TGT AAG CCG GTA TG 5’
the new RNA is 5’ AUG CCG GGU ACA UUC GGC CAU AC 3’
the new amino acid seuquence is : Met-Pro-Gly-Thr-Phe-Gly-His-
Nonsense mutation is due to the point mutation which changes the codon to a stop codon.
the 24 th nucleotide is changed to G
the new DNA sequence is
DNA 5’ ATG CCG GGT ACA TTC GGC CCA TAG 3’
DNA 3’ TAC GGC CCA TGT AAG CCG GGT ATC 5’
the new RNA is : 5’ AUG CCG GGU ACA UUC GGC CCA UAG 3’
the amino acid sequence is Met-Pro-Gly-Thr-Phe-Gly-Pro
a Missense mutation changes the amino acid to another amino acid.
the fourth nucleotide is changed to A
the new DNA is
DNA 5’ ATG ACG GGT ACA TTC GGC CCA TAC 3’
DNA 3’ TAC TGC CCA TGT AAG CCG GGT ATG 5’
new RNA is
RNA 5’ AUG ACG GGU ACA UUC GGC CCA UAC 3’
the amino acid sequence is
Met-Thr-Gly-Thr-Phe-Gly-Pro-Tyr
the second amino acid is changed to Thr.
1. Using the following DNA segment, the RNA transcribed and the translation DNA 5’ ATG CCG...
A single mutation has occurred in the following DNA sequence. 5' ATG AAA TTA CCA 3' wild-type (normal) sequence 5' ATG AAG TTA CCA 3' mutant sequence (a) Identify and classify the mutation according to its molecular structure (i.e., insertion, deletion base substitution (transversion), or base substitution (transition)). Briefly explain why you selected this classification (1.75 marks) (b) Identify and classify the mutation according to its functional effects (i.e., frameshift, missense, nonsense, or silent). Briefly explain why you selected this...
The next DNA sequence is the MATRICE strand of a small gene. What is the complete amino acid sequence of the encoded peptide? GTCATGGCAACATAG 5'-3 Standard Genetic Code First position (5'end) U Second position UAU Tyr UAC Tyr UCA Ser UAA StopUGA Stop UAG Stop UUU Phe UUC Phe UUA Leu UUG Leu UGU Cys UGC Cys UCU Ser UCC Ser UCG Ser UGG Trp CUU Leu CUC Leu CUA Leu CUG Leu CCU Pro CCC Pro CCA Pr CCG...
A single mutation has occurred in the following DNA sequence. 5' ATG TTC CAG CCA 3' wild-type (normal) sequence 5' ATG TTC TAG CCA 3' mutant sequence a) Identify and classify the mutation according to its molecular structure (i.e., insertion, deletion base substitution (transversion), or base substitution (transition)). Briefly explain why you selected this classification. b) Identify and classify the mutation according to its functional effects (i.e., frameshift, missense, nonsense, or silent). Briefly explain why you selected this classification.
Adenosine deaminases modify adenosines to form _____________________, which is then read as _________________________ by the translation and splicing systems, as well as by reverse transcriptase. Cephalopods like squid and octopus use this form of editing very extensively in their protein-coding regions. For each of the following, please indicate how these enzymes can alter the mRNA to produce the indicated codon changes. I (Ileu) is changed to V (val): K (Lys) is changed to E (Glu): T (Thr) is changed to A (ala):...
Describe what kind of mutation this allele has (e.g. insertion, deletion, substitution), which codon it is in, what effect it will have on the protein (e.g. nonsense missense, silent) as well as the amino acid change it will cause if it is a substitution. Refer to the genetic code. U UUU C UCU Uục Phe UCC Ser UUA UUG CUU UCA UCG CCU CCC Α UAU UAC y UGC cys UAA Stop UGA Stop UAG Stop UGG trp CGU CAC"...
A template strand of DNA in a gene reads 3’ CCA AGC TCT 5’. Using the codon chart provided, answer the following questions: -What is the sequence of amino acids that is produced when this gene is translated? -If a mutation causes a substitution (an A instead of a T) 3’ CCA AGC ACT 5’, what effect will it have on the mRNA transcript AND on the protein? -What do we call this type of mutation? Second letter U С...
Bring this DNA sequence to protein using the transcription (3pts) and translation (4 pts) processes. note: Pending the direction your DNA is located Second position UUU Ae UCU UCC cys DU Sey UAU UAC UAA UAG UGU UGC UGA UGG UUA tyr Stop Stop JC Stop CUU CUC his CUA 5 'ATGCCGACGCCATAA 3' Lleve esta secuencia de ADN hasta proteína mediante los procesos de transcripción (3pts) y traducción (4 pts). First position (5'-end) CUC AUU AUC ile AUA AUG met...
4. Using the MK-Test, evaluate whether positive selection has driven the evolutionary divergence between Chimpanzees and Humans, Please show your work.. Second letter U C A UUU Phe UCU UAU UGU UCC Tyr UUA T UAC UAA Stop UGA UAG Stop UGG UGC Cys UCA Ser UUG FLeu UCG Trp G CUUT CUC CUA CCU CCC CCA. CCG CAU CAC His CAA CAG Gln CGU CGC Leu Pro Arg CGA CGG CUG G AUU 1 AUC lle A AUA ACU...
Repo Fill in the needed bases, codon, anticodon, or amino acid needed to complete the following table that relates the sequences of DNA, mRNA, RNA, and the resulting polypeptide. DNA informational strand: 5' end 3' end Guide DNA template strand: 3' end GTC CCC GCG GGG ACG TTG 5' end mRNA codons: 5' end 5' end 0 0 3'end 3' end tRNA anticodons: Polypeptide: TABLE 22.3 The Genetic Code - Triplets in Messenger RNA First Base (5 end) Second Base...
all of them please Question 12 (1 point) Which of the following conditions would kill amp' lac his bacteria? amp = ampicillin (an antibiotic), lac = lactose (a carbohydrate), his = histidine (an amino acid) A) growing the bacteria in media that contained ampicillin, had lactose as the sole metabolic carbon source, and contained the amino acid histidine. B) growing the bacteria in media that contained ampicillin, had lactose as the sole metabolic carbon source, but did not contain the...