You utilise 100 uL of Test Serum, adding 6.0 mL of BCG reagent to the tube....
You utilise 100 uL of Test Serum, adding 6.0 mL of BCG reagent to the tube. Calculate the dilution factor of the serum in the final (working) solution.
Homework Answers
Dilution factor can be calculated initial volume /final volume
= 100/106 = .94
Hence the dilution factor is 0.94 if we add 100 ul of test serum with 6 ul of BCG reagent
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You utilise 100 uL of Test Serum, adding 6.0 mL of BCG reagent
to the tube....
3. A serial dilution of a swab sample was prepared by adding 10 uL to a...
3. A serial dilution of a swab sample was prepared by adding 10 uL to a volume of 990 ML water in tube 1, and 10 uL to a volume of 990 uL water in tube 2. a. What is the overall dilution and dilution factor of each tube? Overall Dilution Dilution Factor Tube 1 Tube 2 b. If 100 uL of tube 2 is spread plated and 126 colonies grow, what was the #cells/mL in the original sample?
B 2 ml 500 ul 1 1.25 ml 500 ul 1 ml Reagent HO 300 mM...
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dilutions dilutions What are the resulting dilutions? Notice units of measurement. a) b) c) 500 L...
dilutions
dilutions
What are the resulting dilutions? Notice units of measurement. a) b) c) 500 L of serum is diluted to 2.0 mL 50 uL of whole blood is pipetted into 0.95 mL of diluent 500 mL of liquid K is added to 4.5 L of water 7. If 10 uL of urine is added to 90 uL of water, and the resulting solution is brought to a final volume of 0.50 mL with water, what is the final dilution...
17. One milliliter of plasma is diluted 1/10 in tube 1. Then 1 mL of the...
17. One milliliter of plasma is diluted 1/10 in tube 1. Then 1 mL of the dilution in tube 1 is added to 4 mL in a second tube. One milliliter from tube 2 is then added to 9 mL diluent in tube 3. What is the substance (plasma) volume in the third tube? 18. What is the specific gravity of a substance if 5 mL of the substance weighs 6.5 g, but the substance is only 50% pure? 19.What...
Lab 5: Additional Dilution Problems You have a stock solution that contains 24 mg/ml of protein....
Lab 5: Additional Dilution Problems You have a stock solution that contains 24 mg/ml of protein. You want to make a set of standards with the following concentrations: 12 mg/ml, 6 mg/ml, 3 mg/ml and 1.5 mg/ml You need a minimum of 500 ul of each standard after all dilutions are completed. Using the technique of serial dilution, explain how you would make your standards by filling in the chart below. Std 4 Std 1 12 Std 2 6 Std...
1) Figure below show a 36 uL of stock solution containing 800 ppm of CuSO4 was...
1) Figure below show a 36 uL of stock solution containing 800 ppm of CuSO4 was transferred into T1 tube contained with 324 uL of wash buffer. Next, serial dilution was performed from T1 to T5. (CuSO4 molar mass: 159.61 g/mol) 36 ul 120 ML 120 ML 120 L 120 L 800 ppm Cuso T1 Stock solution T2 T3 T4 TS B1 Dilution Factor Final Concentration NA 800 ppm Tube Volume Diluent Total Final Transferred Volume Volume Volume (PL) (wash...
You transfer 1 mL of stock solution to tube A, add 9 mL of water and...
You transfer 1 mL of stock solution to tube A, add 9 mL of water and mix. You then transfer 1 mL from tube A to tube B, add 9 mL of water and mix. And finally you transfer 1 mL from tube B to tube C, add 9 mL of water and mix. What is the total dilution factor for this series when comparing the stock solution with tube C? (990 is not the answer)
QUESTION 4 You carry out a dilution adding 20 ml of solution A and 80 mL...
QUESTION 4 You carry out a dilution adding 20 ml of solution A and 80 mL of water. This dilution can NOT be expressed as: o 1 in 4 dilution. O 1:4 dilution. 5 fold dilution. having a dilution factor of 5. 1 in 5 dilution.
3. A serial dilution of a swab sample was prepared by adding 10 uL to a volume of 990 ML water in tube 1, and 10 uL to a volume of 990 uL water in tube 2. a. What is the overall dilution and dilution factor of each tube? Overall Dilution Dilution Factor Tube 1 Tube 2 b. If 100 uL of tube 2 is spread plated and 126 colonies grow, what was the #cells/mL in the original sample?
B 2 ml 500 ul 1 1.25 ml 500 ul 1 ml Reagent HO 300 mM NaPO4 pH 7.4 250 uM DCIP 60 mM succinate 60 mM malonate Tissue Homogenate (add this just before you take the initial reading) 2 750 ul 500 ul 1 ml 500 ul 3 700 ul 500 ul 1 ml 500 ul 50 ul 4 650 ul 500 ul 1 ml 500 ul 100 ul 5 550 ul 500 ul 1 ml 500 ul 200...
dilutions
dilutions
What are the resulting dilutions? Notice units of measurement. a) b) c) 500 L of serum is diluted to 2.0 mL 50 uL of whole blood is pipetted into 0.95 mL of diluent 500 mL of liquid K is added to 4.5 L of water 7. If 10 uL of urine is added to 90 uL of water, and the resulting solution is brought to a final volume of 0.50 mL with water, what is the final dilution...
17. One milliliter of plasma is diluted 1/10 in tube 1. Then 1 mL of the dilution in tube 1 is added to 4 mL in a second tube. One milliliter from tube 2 is then added to 9 mL diluent in tube 3. What is the substance (plasma) volume in the third tube? 18. What is the specific gravity of a substance if 5 mL of the substance weighs 6.5 g, but the substance is only 50% pure? 19.What...
Lab 5: Additional Dilution Problems You have a stock solution that contains 24 mg/ml of protein. You want to make a set of standards with the following concentrations: 12 mg/ml, 6 mg/ml, 3 mg/ml and 1.5 mg/ml You need a minimum of 500 ul of each standard after all dilutions are completed. Using the technique of serial dilution, explain how you would make your standards by filling in the chart below. Std 4 Std 1 12 Std 2 6 Std...
1) Figure below show a 36 uL of stock solution containing 800 ppm of CuSO4 was transferred into T1 tube contained with 324 uL of wash buffer. Next, serial dilution was performed from T1 to T5. (CuSO4 molar mass: 159.61 g/mol) 36 ul 120 ML 120 ML 120 L 120 L 800 ppm Cuso T1 Stock solution T2 T3 T4 TS B1 Dilution Factor Final Concentration NA 800 ppm Tube Volume Diluent Total Final Transferred Volume Volume Volume (PL) (wash...
QUESTION 4 You carry out a dilution adding 20 ml of solution A and 80 mL of water. This dilution can NOT be expressed as: o 1 in 4 dilution. O 1:4 dilution. 5 fold dilution. having a dilution factor of 5. 1 in 5 dilution.
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