A freshly cooked potato is cooling on a plate. The temperature of the potato is observed to drop by 5 oC in the first minute of cooling. Will it cool by more or less than 5 oC in the second minute?
The heat lost by the potato = mass x specific heat x change in temperature
Since the change in temperature with respect to room temperature decreases everytime with passing minutes , the amount of energy released will also be less. In such a case if the temperature dropperd by 5oC in the first minute of cooling , so the potato will cool less than 5oC in the second minute.
A freshly cooked potato is cooling on a plate. The temperature of the potato is observed...
Exercise 1.18 A freshly forged flat steel ( λ-56, 16 W/m K , c.-450 J/kg K, ρ-7800 kg/m2 ) is immersed in an oil bath at 800°C. The steel surface immediately reaches the temperature of the oil bath of 50°C. Neglect marginal effects and consider the steel as a plate with a thickness of 10 mm. What are the steel temperatures in 1 mm, 4 mm and 5 mm below the surface? a) after 1/100 second? b) after 1/10s c)...
2. A 250.0 mL container of gas is at 150.0°C. At what temperature will the gas occupy a volume of 125 mL? (assume constant pressure) puulle Will the gas Dulle constant pressure) 3. An open flask of air is cooled. a. Does it contain more gas molecules before or after cooling? b. is the pressure the same, greater or less than before it was cooled? b. Is the pressure the same, greater or less than before it was cooled? 4....
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QUESTION 1 Two glasses with equal quantities of water are at the same temperature. if the temperature of one is ralsed by 10 C and that of the other is raised by 10K, which one will be hotter? O The temperature of the first glass is more than the second, as each degree on the Celsius scale equals 1.8 degrees on the Kelvin scale. - The temperature of first glass is more than...
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Ball bearings are hardened through a process of heating and then
rapid cooling. The temperature of the ball during this process can
be estimated using the equation:
T(t) = (ti-to)*e^(-t/T)+to
where ti = initial ball temp = 800 degrees celcius
to = initial oil temp = 40 degrees celcius
t = time = 0-180 seconds at 1 second intervals
T = time contraint
Create a graph in matlab showing ball temperature versus time.
the graph should have 3...
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