A) Non- pipelined processor:
Cycle Time: There is no pipelining , so the cycle time has allow an instruction through all the stages each cycle
Cycle Time determines by sum of all stages - 1480ps.
Non -pipeline processor takes 1480 ps.
The latency for an instruction is also the same, since each instruction takes 1 cycle to go from beginning fetch to the end of writeback.
B) Pipelined processor:
Pipelining to 5 stages reduces the cycle time to the length of the longest stage. Additionally, the cycle time needs to be slightly longer to accommodate the register at the end of the stage.
Pipelined Cycle Time determines the slowest stage: 500ps
Pipelined processor takes 5 cycles at 500ps per cycle for total latency of 2500ps.
C)
LW instructions uses all the 5 stages.
Split Memory Access Stage into two stages of 250ps.
New Cycle time is 250ps.
(Pipelining 20%) The 5 stages of a processor have the following latencies: Fetch Decode Execute Memory...
In this exercise, we examine how pipelining affects the clock cycle time of the processor. Problems in this exercise assume that individual stages of the datapath have the following latencies: IF | ID | EX | MEMIwB 200ps 400ps 150ps 250ps 200ps Also, assume that instructions executed by the processor are broken down as follows: alu beqIwSW 45% 20% 20% 15% 3.1 What is the clock cycle time in a pipelined and non-pipelined processor? 3.2 What is the total latency...
In this exercise, we examine how pipelining affects the clock cycle time of the processor. Problems in this exercise assume that individual stages of the datapath have the following latencies: [17pts] 3. IF ID EEX MEM | WB 250ps 350ps 150ps300ps200ps a. what is the clock cycle time in a pipelined and non-pipelined (ie, single cycle) processor? what is the total latency of one lw instruction in a pipelined and non-pipelined (i.e., single cycle) processor? b. What is the total...
The latencies of individual stages in five-stage MIPS (Microprocessor without Interlocked Pipeline Stages) Architecture are given below. Instruction Instruction Fetch Register Read Arithmetic Logic Unit (ALU) Memory Access Register Write Latency 200ps 100ps 200ps 300ps 100ps a. (10 pts) What is the clock cycle time in a pipelined and non-pipelined processor? Pipelined version : ______________ Non-pipelined version : ______________ b. The classic five-stage pipeline MIPS architecture is used to execute the code fragments. Assume the followings: Register write is done...
01. The logic latencies for individual stages in a processor are listed in the following table. IF ID EXE MEM WB 350 ps 400 ps|370 ps450 ns 200 ps (a) What is the minimum clock period for a pipelined and a non- pipelined processor using these parameters? Please show all work. (b) What is total latency of a MIPS lw instruction in a pipelined processor? What is the throughput of a large series of lw instructions with no stalls or...
A 5-Stage pipeline is composed of the following stages Instruction Fetch (IF), Decode (DE), Execute (EX), Memory Access (ME) and Register Write-back (WB). Assume the pipeline does not have a branch prediction unit, does not have superscalar support and does not support out of order execution. Assume that all memory accesses are in the L1 cache and therefore do not introduce any stalls. Show a pipeline diagram that shows the execution of each stage for the assembly code below. Also...
1. Assume that individual stages of the datapath have the following latencies: IF ID EX MEM WB 250 ps 350 ps 150 ps 300 ps 200 ps Also, assume that instructions executed by the processor are broken down as follows: alu beq lw sw 45% 20% 20% 15% What is the total latency of an ?w instruction in a pipelined and non-pipelined processor? Instead of a single-cycle organization, we can use a multi-cycle organization where each instruction takes multiple cycles...
Suppose the times required by each of the functional units of a MIPS processor to do their work are: Instruction Memory: 400 ps Data Memory: 400 ps ALU: 300 ps Register file: 200 ps lgnoring the overhead introduced by the pipeline registers, what is the maximum speedup achieved by the pipelined processor with fetch, decode, execute, memory and write back stages vis-a-vis the single-cycle processor? Give your answer to two decimal places.
A non-pipelined processor has a clock rate of 1 GHz and an average instruction takes 9 cycles to execute. The manufacturer has decided to design a pipelined version of this processor. For this purpose, the instruction cycle has been divided into five stages with the following latencies: Stage 1 – 2.0 ns,Stage 2 – 1.5 ns, Stage 3 – 1.0 ns, Stage 4 – 2.6 ns, Stage 5 – 1.9 ns. Each stage will require an extra 0.4 ns for...
We found that the instruction fetch and memory stages are the critical path of our 5-stage pipelined MIPS CPU. Therefore, we changed the IF and MEM stages to take two cycles while increasing the clock rate. You can assume that the register file is written at the falling edge of the clock. Assume that no pipelining optimizations have been made, and that branch comparisons are made by the ALU. Here’s how our pipeline looks when executing two add instructions: Clock...
6(10%) (Pipelining) Suppose you have a system where every problem must pass through 4 pipeline stages with delays of 30ns, 60ns, 15ns, 20ns. Each stage cannot be replicated, but can be pipelined. (a) What is the minimum number of stages, from beginning to end,in a pipeline that has no load imbalance? (b) What is the clock cycle time for this case, assuming clock to q delay, setup time and hold time is 2ns for registers? 6(10%) (Pipelining) Suppose you have...