Question

10. Spoz we have 200 such cars, and the probability that each car has a mass that is greater than 1400 kg is 0.34. a. How many cars, on the average, have a mass greater than 1400 kg? Manp M= 200 x 0.34 p= 68 cars b. What is the probability that, of the 200 cars, 21 to 45 have a mass greater than 1400 kg? IP(212Z <45 221-68 <3< 45-68 60699 6.699 = 168(1-0.34 26.699 -7:02 <Z<-3.43 Ma 68 &- vnpq = Joplo-p) not sure if this in conce

Answer 1

we have: n = 200, p = 0.34. (a) How many cars, on the average, have a mass greater than 1400 kg? here tet x e Bin Chip) i. mean = np = 2004 0.34 E 68 / cars. 6 what is the probability that, the 200 cars, 21 to 45 have a mass greater than 1400 kg ? * P[215 x = 45] we know that as a-4 m N(01) -

here Ma np= 684 of Sheq = Sup (ip) = 568411-0.34) = 54488 = 6.5992 -> p (264) = (254) < 145_^)] 5) PC celo < 25 (usz Grada ] . =) PC -7.015 325 -3.4332)

- P(Z<- 3.4332] - prz>, 7.015] = !- P(24 – 3.433234 - P[22, -7-015) here we need to use a score table: =(1- 0.0003) - 0.0000.... = 1-0.0003 -0.0000 = 0.9997 cz -4 is o. & Above 3.5 is score equal to for below 1]