S(t) = -16t 2 + v0 t + s0
As the ball is projected from ground level so initial height = 0 = S0
Height of ball after 2 sec
S(2) = -16(2)2 + 112(2) = 160 feet --- Answer
To get maximum height dS(t) / dt
= -32t + vo = 0
32t = 112 or t = 3.5 sec
At t = 3.5 sec height S(3.5) = -16(3.5)2 +112(3.5)
= 196 feet ---- Answer
When ball will reach ground s =0
0 = -16t 2 +112t
16 t 2 = 112t
t = 0 and at t = 7 sec ---- Answer
So t = 7 sec ball will reach ground
Answer
Thank you
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