7.10. Steam expands adiabatically in a nozzle from
inlet conditions of 130(psia), 420(°F),
and a velocity of 230(ft)(s)−1 to a discharge pressure of 35(psia)
where its velocity is
2000(ft)(s)−1. What is the state of the steam at the nozzle exit,
and what is Sg for the
process?
inlet temperature T1 = 420°F
Inlet pressure P1 = 130 psia
velocity of inlet steam u1 =
Velocity of outlet steam u2 = 2000 ft/s
From the steam table
From the energy balance
For an adiabatic process
For horizontal position
final energy balance
H2 - H1 = (230² - 2000²)/2 = - 1973550 ft2/s2 x (1Btu/lbm / 25.037 ft2/s2)
H2 = 1233.6 - 78.825
H2 = 1154.775 Btu/lbm
At 35 psi
From the steam table
Hf = 228.03 Btu/lbm
Hg = 1167.1 Btu/lbm
Sf = 0.3809 Btu/lbm-R
Sg = 1.6872 Btu/lbm-R
From the enthalpy balance
H2 = Hf + x*(Hg - Hf)
1154.775 = 228.03 + x*(1167.1 - 228.03)
x = 0.987
From the entropy balance
S2 = Sf + x*(Sg - Sf)
S2 = 0.3809 + 0.987*(1.6872 - 0.3809)
S2 = 1.67 Btu/lbm-R
Sdotg = S2 - S1
= 1.67 - 1.6310
= 0.039 Btu/lbm-R
7.10. Steam expands adiabatically in a nozzle from inlet conditions of 130(psia), 420(°F), and a velocity...
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