Does a current source (current mirror) need matched transistors ( transistors with the same characterisitics)?
Yes. Let's see an example for better understanding.
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Does a current source (current mirror) need matched transistors ( transistors with the same characterisitics)?
R, Figure P7.49 .50 Figure P7.50 shows a current source realized using a current mirror with two matched transistors Q, and o, . Two equal resistances R, are inserted in the source leads to increase the output resistance of the current source. If Q, is operating at gm 1 mA/V and has VA-= 10 V, and if the maximum allowed de voltage drop across R, is 0.3 V, what is the maximum avail- able output resistance of the current source?...
For the differential amplifier shown in Figure 6: Assume well-matched transistors and = 100 for all transistors: a) Why it is important to use well-matched transistors in differential amplifier circuits? What is the potential influence of mismatched transistors on the performance of the differential amplifier? b) Determine the resistor values (R1, R2 and R3) such that the emitter coupled current IE = 0.5 mA and VC1 = 3 V. c) Draw the ac equivalent circuit for the single ended...
1. Consider the following current mirror combination, where all transistors have the same kn'(W/L) = kp'(W/L) = 2mA/V2, and VTN-1У, VTP--1V. It is also given that VDD1-10V, VDD2-8V. Remember that for saturation the drain current is given by IDー½ k,"(W/L) (VGS-Yn)" for NMOS and ID ½ kp"(WL) (VGS-V,»)2 for PMOS. You can ignore the channel modulation for all transistors. (a) Find the value of R so that I.-1mA. (b) Are transistors Q1, Q2, Q3 in saturation? (c) What is the...
Consider the following current mirror combination, where all transistors have the same kn'(W/L) = kp'(W/L) = 2mA/V2, and VTN = 1V, VTP = -1V. It is also given that VDD1 = 10V, VDD2 = 8V. Remember that for saturation the drain current is given by ID = ½ kn'(W/L) (VGS – VTN)2 for NMOS and ID = ½ kp'(W/L) (VGS – VTP)2 for PMOS. You can ignore the channel modulation for all transistors. Find the value of R so that...
Beta = 100 10 V IRE R3 Fig. 1: A current source and mirror circuits using npn BJTS Design the current source and mirror circuit in Fig. 1 such that IREF = 10 mA (13%) nominally. Use supply of Vcc = 10 V, and use an average value for ß that you found in your previous experiments or that from the datasheet. Find the value of R, that satisfies the design requirements. In your pre- lab, perform the following: 1....
) The current-mirror circuit shown in Figure 3 utilizes pnp transistors having Isl 10-5A and/s2-2x10-5A for transistors Q1 and Q2 respectively and for both transistors a β 50, and |Val 10 V to source a current at Vo.It is required to design the circuit to provide an output current oflo= 1 mA at Vo = 2 V. What values of REF and R are needed? 0i 02 /REF lo ) The current-mirror circuit shown in Figure 3 utilizes pnp transistors...
2. In the following current mirror circuit, Vcc -10V, and the three transistors, Q1, Q2, Q3, have the same saturation current (i.e.,IssIs), and with V for active mode is 0.7V. Then, the three beta values are given by: β91-100, ßQ2-50, and ßQ3-200. The thermal voltage is ντ-25mV. Assuming that you need an output current of i1mA: ref db (a) Find the collector, base, and emitter current for all three Q1 O2 transistors when ia 1mA. (b) Find the refern ie....
transistors, one and L and L 20 μ m, and 40 μ m os current mirror consists of three PMOS e diode connected and two used as current ts. All transistors have lv,1-06 v, k 100 μ A/V" outputsL0μ m but three different widths, namely, 10 μm. m. When the diode-connected transistor is a 100-HA source, how many different output available? Repeat with two of the transistors diode and the third used to provide current output. For le input-diode combination,...
Design a current steering circuit that provides 2 current sinks and one current source with the following characteristics for the transistors: All PMOS and NMOS are matched; lo, each = 125 UA; Kn = 200 A/V2; VT = 0.4 V
when a ray source illuminates a mirror a viewer on the same . The ght ist be coming trom many directions for the light to reflect off in many directions b. The smoothness or roughness of the surface makes no differences light always reflects in many directions many directions. 。e. Light reflects of in all directions because the surface has very small bin ps and valleys.-/ Your answer is correct. When a ray source illuminates a mirror, a viewer on...