Assume a 32-bit number 0x38103060 is being stored into memory location 0x10000000. What is in the...
Assume a 32-bit number 0x38103060 is being stored into memory location 0x10000000. What is in the memory location 0x10000002 if Big Endian or Little Endian is used?
Please provide calculation steps!
Homework Answers
Answer to the above question is-
We know that the lowest address of the 32 bits(4 Bytes) is used for the address of a block of four contiguous bytes.
In 32 bits number there are 4 bytes. In computer there are two ways to be made about which byte of memory gets what part of number.
- Little Endian
- Big Endian
In Little Endian mechanism , the last byte(Least significant byte) of binary representation of the number is stored first.
In Big Endian mechanism, the first byte(Most significant byte) of binary representation of the number is stored first.
So we can clearly see(in above image) that at memory location 0x10000002 ,
In Big Endian 30 present.
In Little Endian 10 present.
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