The student declared that the top 4% of times made her late to class. Find the minimum time where this time or higher would place the trip time in the top 4% of all times. Draw a picture (or two), shade the area, and use the standard normal table to solve this problem. You must type the rest of your “by hand” work to earn full credit. Given mean =33.1 and standard deviation =1.8
Ans:
Given that
mean =33.1
standard deviation =1.8
For top 4%:
P(Z>z)=0.04
P(Z<=z)=1-0.04=0.96
z=normsinv(0.96)
z=1.75
minimum time=33.1+1.75*1.8
minimum time=36.25
The student declared that the top 4% of times made her late to class. Find the...
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