Question

Calculate the total torque (magnitude and direction) for each of the following cases shown below. You can assume the "bar" the masses are attached to is massless. The top point of the triangle represents the pivot point for the system. Be sure to include the magnitude and the direction.

Calculate the total torque (magnitude and direction) for each of the following cases shown below. You can assume the bar the masses are attached to is massless. The top point of the triangle represents the pivot point for the system. Be sure to include the magnitude and the direction. (a) Here m = 10 g and d = 20 cm. (b) Here m = 10 g and d = 20 cm. magnitude direction r-clockwise 20 cm. (c) Here m1 = m2 = 10 g and d1 = d2 magnitude ONm o direction d) Here m1 m2-10 g and d1-20 cm and d - 1.1 m (d) Here m1-m2-10 g and d1 = 20 cm and d2 = 1.1 m. magnitude

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Answer #1

a)

torque = 10*10^-3*9.8 *0.20 =0.0196​ N.m CW

b)

torque = 10*10^-3 *0.20 =0.0196​ N.m ACW

c)

10*10^-3 *0.20 - 10*10^-3 *0.20 = 0 N.m no direction

d)

10*10^-3*9.8 *0.20 - 10*10^-3*9.8 *1.1 = 0.0882 N.m ACW

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