3. How would you make 200 ml of a 250 mM phosphate buffer from a 1M...

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Answer 1

Answer #1

3. We use the dilution law: Molarity * Volume = constant from the fact that moles of compound remains the same.

Using the initial volume of stock solution to be V, putting in the given values, we get:

1 * V = 250 * 10^-3 * 200

SOlving, V = 50 ml

Therefore we take 50 mL of the 1 M solution and add 150 mL of water to it to get 200 mL of 250 mM of solution.

Answer 2

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