(Adapted from Figure 4–20 of Aiba et al.) Mixed cultures of bacteria can develop into predator–prey relationships. Such a system might be cultures of Alcaligenes faecolis (prey) and Colpidium compylum (predator). Consider two different cells X1 and X2 in a chemostat. Cell X, only feeds on the substrate and cell X2 only feeds on cell X-1.
The growth laws are
(a) For a dilution rate of D = 0.04 h−1, an entering substrate concentration of 250 mg/dm3, initial concentrations of cells of Xu = 25 mg/dm3, X2i= 1 mg/dm3 and of substrate Csi- = 10 mg/dm3, plot CX1 , Cx2, r-gX1 , rgX2 , and Cs as a function of time.
(b) Vary D between 0.01 h−1and 0.1 h−1, and describe what you find.
(c) Vary CS0and CSi- from the base case and describe what you find.
(d) List ways you can work this problem incorrectly.
(e) How could you make this problem more difficult?
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