The following data were obtained for Pyrodictium
ccultum at 98 °C. Run 1 was carried out in the absence of yeast extract and run 2 with yeast extract. Both runs initially contained Na2S. The vol % of the growth product H2S collected above the broth was reported as a function of time. [Ann. N.Y. Acad. Sci., 506, 51 (1987).]
Run 1:
Time (h) | 0 | 10 | 15 | 20 | 30 | 40 | 50 | 60 | 70 |
Cell Density (cells/mL) X 10−4 | 2.7 | 2.8 | 15 | 70 | 400 | 600 | 775 | 600 | 525 |
% H2S | 0.5 | 0.8 | 1.0 | 1.2 | 6.8 | 4.7 | 7.5 | 8.0 | 8.2 |
Run 2: |
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Time (h) | 0 | 5 | 10 | 15 | 20 | 30 | 40 | 50 | 60 |
Cell Density (cells/mL) X 10−4 | 2.7 | 7 | 11 | 80 | 250 | 350 | 350 | 250 | — |
% H2S | 0.1 | 0.7 | 0.7 | 0.8 | 1.2 | 4.3 | 7.5 | 11.0 | 12.3 |
(a) What is the lag time with and without the yeast extract?
(b) What is the difference in the specific growth rates, p.max, of the bacteria with and without the yeast extract?
(c) How long is the stationary phase?
(d) During which phase does most of the production of H2S occur?
(e) The liquid reactor volume in which these batch experiments were carried out was 0.2 dm3. If this reactor were converted to a continuous-flow reactor, what would be the corresponding wash-out rate?
(f) List ways you can work this problem incorrectly.
(g) How could you make this problem more difficult?
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