Problem

Solutions For An Introduction to Genetic Analysis Chapter 6 Problem 43P

Step-by-Step Solution

Solution 1

Step #1 of 3

Determine the genotypes of the parents in the following way:

The given genotypes and phenotypes are:

A/- Yellow A/-; R/- Gray

R/- Black a/a; r/r White

Cross the alleles of Grey with Yellow, we get

Parental genotypes A/-; R/- X A/-; r/r

F₁ progeny

3/8 yellow

1/8 black

3/8 gray

1/8 white

Step #2 of 3

For F₂ progeny, both parents should carry the r and a allele for producing white coat.

Hence the cross could be rewritten as

F₂ progeny A/a; R/r X A/a; r/r

Step #3 of 3

The resultant genotypes and phenotypes are as follows:

Sl. No.	Alleles	Genotypes	Phenotypes
1	AArr, Aarr	3/8	yellow
2	aaRr	1/8	black
3	AARr, AaRr, aARr	3/8	gray
4	aarr	1/8	white

If the alleles a and r are carried with other alleles in F1 progeny, then the resultant F₂would be as expected ratios that is 3/8 yellow :1/8 black : 3/8 gray : 1/8 white.

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Solutions For Problems in Chapter 6

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