Problem

Solutions For An Introduction to Genetic Analysis Chapter 6 Problem 51P

Step-by-Step Solution

Solution 1

Petal coloration in foxgloves is determined by three genes:

1. M encodes an enzyme, which synthesizes anthocyanin, the purple pigment is seen in petals, m/m produces no pigment. This results in the phenotype of albino with yellowish spots.

2. D is an enhancer of anthocyanin, which results in darker pigments; d/d does not enhance. In contrast, at the third locus, w/w allows pigment deposition in petals, but W prevents pigment deposition except in the spots. So the results in the white, spotted phenotype is observed in the following crosses.

In the following two crosses:

Cross 1:

M/-; D/-; w/w (dark purple) X m/m; ?/?; ?/? (White with yellowish spots)

F 1 :

½ M/-; D/-; w/w dark purple

½ M/-; d/d; w/w light purple

The presence of color in the progeny indicates that there is an absence of W allele in the parents. And the ratio indicates that one gene in the parents is heterozygous. The presence of d/d indicates a light purple progeny giving the genotypes

Parent:

M/M; D/d; w/w X m/m; d/d; w/w

F 1 :

½ M/m; D/d; w/w

½ M/m; d/d; w/w

Cross 2:

When m/m; ?/?; ?/? (White with yellowish spots) X M/-; d/d; w/w (light purple)

F 1 :

½ M/-; ?/?; W/- white with purple spots

¼ M/-; D/-; w/w dark purple

¼ M/-; d/d; w/w light purple

The ratio of dark colored to the light purple colored plant indicates that one of the parents must be heterozygous, while a 1:1 ratio indicates that it is a test cross. The presence of purple color in all the plants shows that one parent is homozygous (M/M).

Therefore, the genotypes are:

If a cross between m/m; D/d; W/w X M/M; d/d; w/w

F 1 :

½ M/m; -/d; W/w

¼ M/m; D/d; w/w

¼ M/m; d/d; w/w

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