Solutions For An Introduction to Genetic Analysis Chapter 18 Problem 10P

631190-18-10P AID: 2498 | 24/12/2015

Use Hardy-Weinberg equilibrium

p = frequency of the dominant allele in the population

q = frequency of the recessive allele in the population

Here,

So, FF = 0.5625, FS = 0.375, and SS = 0.0625.

Multiplying these genotypic frequencies with the population size gives, 270 FF progeny, 180 FS progeny, and 30 SS progeny, and finally the total number of individuals is 480.