Answer:
Information provided is as under:
L = Lead time |
5 |
day |
d = Average Demand during the lead time = Daily Demand = |
25 |
units |
N = Number of kanbans = |
18 |
|
S = Safety stock = |
5 |
units |
C = Kanban size |
? |
units |
Kanban size = Number of computers each kanban hold= C =[(d*L) + S]/N = ((25*5)+5)/18 = 7.22 unit of computer
Kanban size **This can be rounded as per requirement.
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