how many times should a restriction enzyme with a recognition of TCGA cut a DNA sequence of 1000 bases?
a) 2
b)4
c) 8
d) 16
e) 32
The answer is b) 4.
The steps inolved here is,
Step:1: Probability of occurnce of restriction site for TCGA sequence:
As one nitrogen base can occupay in one nucleotide position out of four, the probability of each base is 1/4.
So, the probability of TCGA sequence is 1/4*1/4*1/4*1/4= 1/256.
Step 2: Finding the number of restriction sites for 1000 bases DNA sequence=
No of bases in DNA sequences * probability of restriction site for TCGA sequence
= 1000*1/256 = 3.90 = ~4.
So, the answer is 4.
how many times should a restriction enzyme with a recognition of TCGA cut a DNA sequence...
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