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The Number of blows in standard proctor test is Select one: a. three b. five C....
(b) The results of a standard Proctor test are given in the Table Q1. The volume...
(b) The results of a standard Proctor test are given in the Table Q1. The volume of the proctor mould used was 1000 cm? The specific gravity (G) of the soil is 2.65. (1) Plot the graph of dry density (kg/m?) against moisture content (%), the zero air void line (ZAV) and determine the maximum dry density and optimum moisture content. Table Q1: Standard Proctor test result Mass of wet soil in Moisture the mould (kg) content (%) 1.75 13...
Name: 12. Which of the following represents the correct standard proctor test procedure? a. 3 soil...
Name: 12. Which of the following represents the correct standard proctor test procedure? a. 3 soil layers, with 30 blows per layer using a 5.5 lb hammer dropped a distance of 12 inches b. 3 soil layers, with 25 blows per layer using a 10 lb hammer dropped a distance of 12 inches c. 5 soll layers, with 30 blows per loyer using a 10 lb hammer dropped a distance of 10 inches d. 3 soll layers, with 25 blows...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil (kg) 1 1.633 Standard Proctor Test 2 . 1.841 1.907 1.822 1.756 Moisture Content Test 14 14 Mass of tin empty (g) Mass of tin + wet sample (g) Mass of tin + dry sample (g) 98 62 878280 (a) Calculate moisture content (w) and dry unit weight (ya) for standard Proctor compaction tests. Plot moisture content (w) vs. dry unit weight (yd). Given:...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft are given below Weight of wet soil Water content in the mold (Ibs 3.26 4.15 4.67 4.02 3.63 8.4 10.2 12.3 14.6 16.8 a) Plot the data on a plot of dry unit weight versus water content and determine the maximum dry unit weight and the optimum water content. As the geotechnical engineering consultant involved in the project, based on the results obtained in...
A compaction test was conducted in a soils laboratory, and the Standard Proctor compaction procedure (ASTM...
A compaction test was conducted in a soils laboratory, and the Standard Proctor compaction procedure (ASTM D 698) was used. The weight of a compacted soil specimen plus mold was determined to be 4200 g. The volume and weight of the mold were 1/30 ft and 2100 g, respectively. The water content of the specimen was 9.1%. The wet unit weight of the compacted specimen is ᎢbᎴ3 .
Problem 1 (3 points) The results of a standard Proctor test are given in the following...
Problem 1 (3 points) The results of a standard Proctor test are given in the following table. Moisture Mass of moist soil in the mold (R) Trial no. 1668 1723 1800 1850 1873 8.9 12 1868 a. Determine the maximum dry unit weight of compaction and the opti- mum moisture content. Given: Mold volume = 943.3 cm'. b. Determine the void ratio and the degree of saturation at the optimum moisture content. Given: G, = 2.73 Problem 2 (4 points)...
3. For a given soil, a liquid limit test results are given bellow. Number of blows,...
3. For a given soil, a liquid limit test results are given bellow. Number of blows, N 20 Moisture Content (%) 24.1 22.4 21.7 21.3 29 34 a. Determine the liquid limit (LL) of the soil b. Determine the flow index c. If PI = 6.7, determine the plastic limit (PL) of the soil d. The soil moisture content Win situ = 24.8% calculate the liquidity index of the soil.
A test consists of 60 multiple choice questions, each with five possible answers, only one of...
A test consists of 60 multiple choice questions, each with five possible answers, only one of which is correct. Find the mean and the standard deviation of the number of correct answers. Round the answers to the nearest hundredth. ООО A. mean: 12.00; standard deviation: 3.10 B. mean: 30.00; standard deviation: 5:48 c. mean: 12.00; standard deviation: 3.46 D. mean: 30.00; standard deviation: 3.10 Click to select your answer.
The data from a standard Proctor test are shown in the table below. a) Determine the...
The data from a standard Proctor test are shown in the table below. a) Determine the maximum dry unit weight and the optimum water content. b) Plot the zero air voids line. c) Determine the degree of saturation at the maximum dry unit weight. Mass of Mass of Mass of Mass of WaterMass of Bulk can content wet soilmit (grams)(grams) weight kN/m 4.8 1709.517.80 6.8 1816.5 18.91 10.0 1938.5 20.18 11.6 1959.5 20.40 13.21906.519.85 wet soicaand can and and moldtsoil...
Question Help Use the one-standard deviation ?-test and the one-standard deviation je interval procedure to conduct...
Question Help Use the one-standard deviation ?-test and the one-standard deviation je interval procedure to conduct the required hypothesis tout and obtain the specified confidence interval for a sample of on-25 wa standard deviation of s7 a. Hy 5, H > 5,0 -0.025 b. 95% confidence interval Click the icon to view a portion of the y distribution table. a. Compute the test statistic (Round to three decimal places as needed.) Find the critical value(s) (Round to three decimal places...
(b) The results of a standard Proctor test are given in the Table Q1. The volume of the proctor mould used was 1000 cm? The specific gravity (G) of the soil is 2.65. (1) Plot the graph of dry density (kg/m?) against moisture content (%), the zero air void line (ZAV) and determine the maximum dry density and optimum moisture content. Table Q1: Standard Proctor test result Mass of wet soil in Moisture the mould (kg) content (%) 1.75 13...
Name: 12. Which of the following represents the correct standard proctor test procedure? a. 3 soil layers, with 30 blows per layer using a 5.5 lb hammer dropped a distance of 12 inches b. 3 soil layers, with 25 blows per layer using a 10 lb hammer dropped a distance of 12 inches c. 5 soll layers, with 30 blows per loyer using a 10 lb hammer dropped a distance of 10 inches d. 3 soll layers, with 25 blows...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil (kg) 1 1.633 Standard Proctor Test 2 . 1.841 1.907 1.822 1.756 Moisture Content Test 14 14 Mass of tin empty (g) Mass of tin + wet sample (g) Mass of tin + dry sample (g) 98 62 878280 (a) Calculate moisture content (w) and dry unit weight (ya) for standard Proctor compaction tests. Plot moisture content (w) vs. dry unit weight (yd). Given:...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft are given below Weight of wet soil Water content in the mold (Ibs 3.26 4.15 4.67 4.02 3.63 8.4 10.2 12.3 14.6 16.8 a) Plot the data on a plot of dry unit weight versus water content and determine the maximum dry unit weight and the optimum water content. As the geotechnical engineering consultant involved in the project, based on the results obtained in...
A compaction test was conducted in a soils laboratory, and the Standard Proctor compaction procedure (ASTM D 698) was used. The weight of a compacted soil specimen plus mold was determined to be 4200 g. The volume and weight of the mold were 1/30 ft and 2100 g, respectively. The water content of the specimen was 9.1%. The wet unit weight of the compacted specimen is ᎢbᎴ3 .
Problem 1 (3 points) The results of a standard Proctor test are given in the following table. Moisture Mass of moist soil in the mold (R) Trial no. 1668 1723 1800 1850 1873 8.9 12 1868 a. Determine the maximum dry unit weight of compaction and the opti- mum moisture content. Given: Mold volume = 943.3 cm'. b. Determine the void ratio and the degree of saturation at the optimum moisture content. Given: G, = 2.73 Problem 2 (4 points)...
3. For a given soil, a liquid limit test results are given bellow. Number of blows, N 20 Moisture Content (%) 24.1 22.4 21.7 21.3 29 34 a. Determine the liquid limit (LL) of the soil b. Determine the flow index c. If PI = 6.7, determine the plastic limit (PL) of the soil d. The soil moisture content Win situ = 24.8% calculate the liquidity index of the soil.
A test consists of 60 multiple choice questions, each with five possible answers, only one of which is correct. Find the mean and the standard deviation of the number of correct answers. Round the answers to the nearest hundredth. ООО A. mean: 12.00; standard deviation: 3.10 B. mean: 30.00; standard deviation: 5:48 c. mean: 12.00; standard deviation: 3.46 D. mean: 30.00; standard deviation: 3.10 Click to select your answer.
The data from a standard Proctor test are shown in the table below. a) Determine the maximum dry unit weight and the optimum water content. b) Plot the zero air voids line. c) Determine the degree of saturation at the maximum dry unit weight. Mass of Mass of Mass of Mass of WaterMass of Bulk can content wet soilmit (grams)(grams) weight kN/m 4.8 1709.517.80 6.8 1816.5 18.91 10.0 1938.5 20.18 11.6 1959.5 20.40 13.21906.519.85 wet soicaand can and and moldtsoil...
Question Help Use the one-standard deviation ?-test and the one-standard deviation je interval procedure to conduct the required hypothesis tout and obtain the specified confidence interval for a sample of on-25 wa standard deviation of s7 a. Hy 5, H > 5,0 -0.025 b. 95% confidence interval Click the icon to view a portion of the y distribution table. a. Compute the test statistic (Round to three decimal places as needed.) Find the critical value(s) (Round to three decimal places...
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