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strand above write the new mRNA and make a mutation then translate it please explain also...

strand above write the new mRNA and make a mutatio

strand above write the new mRNA and make a mutation then translate it please explain also what the mutation did

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Answer #1

5' TAATGCTAGACGTGTTCTAGGA 3' (coding strand) mRNA strand will be same as coding strand except T by U

3 ' ATTACGATCTGCACAAGATCCT 5' (template strand)

5' UAA UGC UAG ACG UGU UCU AGG A 3' mRNA

Stop C Stop T C S R protein sequence has stop codons

the above mentioned sequence is

5' UAA UGC AGA CGU GUU CUA GGA 3'

Stop C R R V L G due to stop codon peptide is not translated

by mutating first residue in the coding DNA to G we gaet the GAA in place of UAA so

the new mRNA is

5' GAA UGC AGA CGU GUU CUA GGA 3'

E C R R V L G protein sequence no stop codons are there so the protein sequence is translated we get a new peptide sequece which have no stop codons incorporated

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