Homozygous recessive individual parcentage is 16% . So let the whole population be 100 . Then recessive individual will be 16 . Now we can say according to Hardy Weinberg equilibrium q2 = 0.16 so q = 0.4 so, p= 0.6 and 2pq= (0.4 x 0.6)x2 = 0.48 so parcentage of heterozygous population will be 48 or 48 % population is heterozygous
Consider a randomly-mating population that is not evolving. If the population consists of 16% homozygous recessive...
If individuals homozygous for a recessive mutation make up 16% of a population at Hardy-Weinberg equilibrium, the frequency of heterozygous individuals would be a. 84% b. 36% c. 24% d. 48% What percentage of the population are heterozygous? a. 42% b. 0.42 c. 97% d. 91% e. 94% If you sample diatoms Parisians 100 years from now, what should be the frequency of individuals with short antennae? a. 0.09 b. 0.91 c. 0.095 d. 0.03
A mating between a heterozygous individual and a homozygous recessive individual results in 11 heterozygous progeny and 22 homozygous individuals. Do these observations fit a hypothesis of a 1:1 ratio of phenotypes? Conduct a Chi-square test to determine if these observations fit the hypothesis. Include: 1. The Chi-square value 2. The number of degrees of freedom 3. The p-value 4. Interpret what the p-value means. HTML Editor
Consider the following scenario: In a population of 1000 individuals, 490 are homozygous dominant, 420 are heterozygous, and 90 are homozygous recessive. Answer the following questions about this population. How many total alleles does this population have? How many dominant alleles does this population have? How many recessive alleles does this population have? Based on your numbers from part a, calculate the following frequencies, and give a written description of each (i.e. what does each number mean in “real world”...
A randomly mating population of dairy cattle contains an autosomal-recessive allele causing dwarfism. If the frequency of dwarf calves is 10%, what is the frequency of heterozygous carriers of the allele in the entire herd?
In a hypothetical population which is in Hardy Weinberg equilibrium, the frequency for a recessive allele is 30%. What percentage of the population would be expected to show the dominant trait in the next generation? Humans who are born homozygous for the recessive sickle cell allele die of sickle cell anemia, while those who are heterozygous are resistant to malaria (see chapter 4 for more information on this balanced polymorphism). 4% of the population of the Congo are homozygous recessive for...
Question 7 4 pts A trait (or, phenotype) due to homozygous recessive mutation in a large randomly mating population affects 1 in 1,000 diploid individuals. What is the allele frequency for this recessive allele, assuming the population is in Hardy-Weinberg equilibrium? O 0.001 O 0.031 O 0.1 0 1
In a population that meets Hardy- Weinberg equilibrium assumptions, 81% of the individuals are homozygous for the recessive allele. What percentage of the individuals would be expected to be heterozygous for this locus in the next generation?
please click on the photo to see all of it The basic equations of Hardy-Weinberg Equilibrium p² + 2pq + q2 = 1 p+q=1 p= frequency of the dominant allele in the population 9 = frequency of the recessive allele in the population př= percentage of homozygous dominant individuals q* = percentage of homozygous recessive individuals 2pq - percentage of heterozygous individuals 1. You have sampled a population in which you know that the percentage of the homozygous recessive genotype...
In a large random mating population of plants, 16,800 individuals express the phenotype of the dominant allele (genotypes AA and Aa) and 3200 express the phenotype of the recessive allele (genotype aa). a. What are the frequencies of the two alleles in this population? b. How many plants would be expected to heterozygous? c. You decide to select for the recessive phenotype and pull up 50% of the plants expressing the dominant phenotype. What will be the gene frequencies of...
genetics problem: 5. On a small island, 235 mating individuals are all homozygous for brown eyes. An epidemic wipes out all but 10 young women, 2 young men, and two elderly women (both >70 years old). A boatload of foreigners arrives; the foreign population consists of six heterozygous brown-eyed young women, four homozygous brown-eyed young men, and 10 blue-eyed young men. Assuming that eye color is controlled by a single locus with the brown allele being dominant (blatantly incorrect, but...