Question

NEED ANSWER D.

The Pullman Mfg., Inc. three-station work cell illustrated in the figure below has two machines at station 1 in parallel. (The product needs to go through only one of the two machines before proceeding to station 2.) 12 min/unit Station 1 Machine A Station 2 Station 3 5 min/unit 12 min/unit Station 1 Machine B 12 min/unit The manager, Ms. Hartley, has asked you to evaluate the system if she adds a parallel machine at station 3. a) The throughput time of the new work cell is 29 minutes (enter your response as a whole number). b) The bottleneck time of the new work cell is 6 minutes per unit (enter your response as a whole number). c) If the firm operates 8 hours per day, 6 days per week, the weekly capacity of the work cell with the second machine at workstation 3 is 480 units (enter your response as a whole number). d) If the firm operates 8 hours per day, 6 days per week, the weekly capacity of the work cell without the second machine at workstation 3 is number). units (enter your response as a whole

Answer 1

Output per hour from a station = Number of machines*60/process time

Station 1 = 2*60/12 = 10 units per hour

Station 2 = 1*60/5 = 12 units per hour

Station 3 = 1*60/12 = 5 units hours

a) Throughput time = Cycle time = Bottleneck station time which is station 3 = 12 min

b) Bottleneck is station 3 with time 12 min per unit

c) If second machine is added in station 3, the output per hour will be 2*5 = 10 units

So, process output rate is 10 units per hour

Weekly capacity = Output per hour*Hours per day*Days per week = 10*8*6 = 480 units

d) If there is no second machine in station 3, output per hour of the process will be output per hour of station 3 which is 5 units

Weekly capacity = 5*8*6 = 240 units