Ans. Let the dominant allele for height = T
The recessive allele for height = t
Genotype of heterozygous tall plant = T t
Gametes produced by it = T, t
Genotype of homozygous small plant = t t
Gametes produced by it = t
Now, Tt x tt
[T, t] x [t] = Tt, tt
Total number of progeny = 2 , (Tt and tt)
Phenotypic ration = Tall : short = 1: 2
So, if the total number of progeny were 50, the theoretical outcomes would have been 25 tall and 25 short (1:1 ratio).
So,
Ans. a. Theoretical (expected) phenotypic frequency = 25 : 25
Ans. b. See figure
Ans. c. degree of freedom = 1
GENETICS: Assume that a cross is made between a heterozygous tall pea plant and a homozygous...
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