Question

Biomolecular Techniques EXPERIMENT 2: RESTRICTION ENDONUCLEASES Data Tables Purpose (What question is this experiment designed to answer?): Does the fragment size affect the enzyme? Hypothesis (Based on what you've learned in the pre-lab materials, write and If/Then statement regarding the outcome of this experiment.) Table 1: Enzyme Analysis Cuts Between Number of Fragments Fragment Size (in order) 22,9,4 17,11,7 3 Enzyme 1 Enzyme 2 Enzyme 3 4 5,3,15,12 ОО Claim (What are the results of your experiment?) Evidence (What data did you collect that supports your claim? Explain the meaning behind the data and the calculations.) Post-Lab Questions 1. Which of the enzymes cut the DNA (bead) sequence into most segments? Which enzyme cut the DNA (bead) sequence into the fewest segments? Enzyme 3 cut the DNA into the most segments Enzymes 1 and 2 both cut the same amount of DNA fragments 100% 10:08 PM 7/10/202 hp

what is the purpose, claim,hypothesis and evidence for restriction endonucleases lab

Answer 1

Restriction endonucleases are enzymes that cleave nucleic acids at or in the vicinity of a given specific (recognition) site on the nucleic acids. As a result of the cleavage, multiple bands are formed from 1 intact nucleic acid molecule. The number of fragments formed depend on the number of recognition sites present on that particular nucleic acid molecule.

Purpose of the experiment: To determine whether the enzymes under study are endonucleases and are able to cleave the given nucleic acid template molecule.

Hypothesis: The enzymes are endonucleases and cleave the given nucleic acid molecule.

If this hypothesis holds true, then find the number of recognition sites present in the given nucleic acid molecule.

Claim: The 2 enzymes under study are endonucleases wither enzyme 1 having 2 recognition sites, enzyme 2 having 2 recognition sites and enzyme 3 having 3 recognition sites. ( Here, we are assuming that the template nucleic acid is a linear molecule).

Evidence: The number of fragments tells us about the number the recognition sites. Assuming that it's a linear nucleic acid molecule, cleaving at 1 site would result in 2 fragments, hence the number of sites will be 1 less that the number of fragments formed.
The size of the fragments tell us about the location of the recognition and/or cleavage sites.