In humans, brown (B) eye color is dominant to blue (b) eye color and brown (H)...
In humans, brown (B) eye color is dominant to blue (b) eye color and brown (H) hair color is dominant to red (h) hair color. [Assume single-gene traits]
Of only the offspring that have brown eyes and brown hair (B_H_, where dash indicates that the individual could be either homozygous or heterozygous for the dominant allele), what proportion are expected to have a genotype that is heterozygous for one of the traits but homozygous for the other trait?
A) 1/4
B) 9/16
C) 1/3
D) 4/9
E) 3/16
Curly hair (C) is dominant to straight hair (c). Gene C and Gene B (eye color) are linked. An individual that is homozygous dominant for both gene C and gene B mates with an individual that is homozygous recessive for gene C but heterozygous for gene B. What is the correct genotype for the mating described?
A) C/c; B/b x c/c;B/B
B) C/c; B/b x c/c; B/b
C) CB/CB x CB/cb
D) CC/BB x CC/bb
E) CB/CB x cB/cb
F) CC/BB x cc/BB
G) CB/cb x Cb/cb
In the cross described in question above, what proportion of the offspring will be homozygous for gene B?
Homework Answers
Q1)
For offspring that show the Dominant Phenotype for both traits (B_ H_), 2/3 will be Heterozygous for either trait (Bb or Hh). Similarly 1/3 will be Homozygous for either trait (BB or HH).
Therefore,
Proportion of Progeny to remain Homozygous for one trait and
Heterozygous for the other = 2 * 2/3 * 1/3 = 4/9
Note that the proportion of such progeny is given by twice the fraction (2/3 * 1/3), since the condition is fulfilled either if the progeny is BbHH or BBHh.
Answer --> D) 4/9
Q2)
Cross
C/C ; B/B x c/c ; B/b
or
CB/CB x cB/cb
Since Parent 1 is Homozygous domianant for both loci, their genotype is CB/CB. Parent 2 is Homozygous recessive at the the Hair locus (cc) and Heterozygous at the Eye color locus (Bb).
Therefore, the cross is diagrammed as CB/CB x cB/cb
Answer --> E)
Q3)
In the cross above, Parent 1 is Homozygous dominant at the 'B' locus (Genotype BB) and Parent 2 is Heterozygous (Bb). This means all the gametes of Parent 1 will have the B allele while 50% (1/2) of gametes of Parent 2 will have the B allele.
Therefore, 1/2 the offspring will be Homozygous for gene B.
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