Question 4 [10 Marks]
The table below shows the percentage of population below poverty level in ten localities, as determined in the years 1990 and 1998.
Locality |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
1998 |
11.6 |
9.8 |
10.1 |
8.7 |
20.4 |
11.2 |
13.1 |
10.4 |
16.6 |
13.7 |
1990 |
7.5 |
13.4 |
13.7 |
10.7 |
20.9 |
11.5 |
14.4 |
13.1 |
13.7 |
16.2 |
(a)
This is paired data , because for the same locality poverty level is measured twice: in 1998 and 1990.
(b_
Summary statistics is got as follows:
Values of d = Poverty level of 1998 - Poverty level of 1990 are got as follows:
d = 4.1 - 3.6, - 3.6, - 2.0, - 0.5, -0.3, -1.3, - 2.7, 2.9, - 2.5
From d values, the following statistics are calculated:
n = 10
= - 9.5/10
= - 0.95
sd = 2.6180
SE = sd/
= 2.6180/
= 0.8279
(c)
=0.05
ndf = n - 1 = 10 - 1 = 9
From Table, critical values of t = 2.2622
Confidence interval:
- 0.95 (2.2622 X
0.8279)
= - 0.95 1.8728
= ( - 2.8228 , 0.9228)
Confidence Interval:
- 2.8228 < <
0.9228
(d)
Based on that confidence interval, there is no sufficient evidence to conclude that the poverty level changed overall between 1990 and 1998 because 0 is included in the confidence interval.
(e)
Sample Size (n) is given by:
Given:
= 0.05
From Table, critical values of Z = 1.96
= 2.6180
e = 0.01
Substituting, we get:
= 263301
So,
Answer is:
263301
Question 4 [10 Marks] The table below shows the percentage of population below poverty level in...
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Year
Poverty Rate
1986
10.9
1987
10.7
1988
10.4
1989
10.3
1990
10.7
1991
11.5
1992
11.9
1993
12.3
1994
11.6
1995
10.8
1996
11
1997
10.3
1998
10
1999
9.3
2000
8.7
2001
9.2
2002
9.6
2003
10
2004
10.2
2005
9.9
2006
9.8
2007
9.8
2008
10.3
2009
11.1
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Sales (Y)
Calls (X1)
Time (X2)
Years (X3)
Type
47
167
12.9
5
ONLINE
47
167
16.1
5
ONLINE
44
165
14.2
5
GROUP
43
137
16.6
4
NONE
34
184
12.5
4
GROUP
36
173
14.3
4
GROUP
44
160
14.1
4
NONE
34
132
18.2
4
NONE
48
182
14.1
4
ONLINE
41
158
13.8
4
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38
163
10.8
4
GROUP...
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