given
molecular mass of protein= 50000 Da
= 50000 gram/mole
(A) Molarity (M) = {amount of solute (gram)/ mw of solute (gram/mole) }/ 1L
40 X 10-6 mole/ Litre= {amount of protein (gram)/ 50000 gram/mole) }/ 1L 1 Micromole = 10-6 mole
amount of protein = 0.20 gram/ Litre
= 0.20 X10-3 gram/ mL
(B)
mass / volume percent= mass of solute (gram)/volume of solution (mL) X 100
= 0.20 X10-3 gram/ mL X100
=0.02 % Answer
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