DNA fragments cut by most restriction enzymes have: double-stranded complementary ends. either only sequences of Gs...
DNA fragments cut by most restriction enzymes have:
double-stranded complementary ends.
either only sequences of Gs or only sequences of Cs.
cuts made at random points along one of the strands.
protruding sticky ends.
Homework Answers
double-stranded complementary ends.
Restriction endonucleases recognize recognition sequences that are most palindromes, i.e. they are complimentary strands that read in opposite direction.
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DNA fragments cut by most restriction enzymes have:
double-stranded complementary ends.
either only sequences of Gs...
find the errors Restriction enzymes recognize specific DNA sequences and cut each strand of DNA at...
find the errors
Restriction enzymes recognize specific DNA sequences and cut each strand of DNA at specific locations at the target sequence. The result of digesting a particular genome with a particular restriction enzyme is a collection of restriction fragments of defined length and composition. These can be used to generate restriction maps or create pieces with sticky ends. These sticky ends can be used to attach to other fragments that have sticky ends caused by cutting with a different...
15- Which option BEST describes sticky ends by restriction enzymes B. Sticky ends A. Sticky ends...
15- Which option BEST describes sticky ends by restriction enzymes B. Sticky ends A. Sticky ends are DNA fragments that carry a higher charge than normal after they have been cleaved are DNA fragments cleaved by a restriction enzyme so that one strand is longer than the other C. Sticky ends are DNA fragments cleaved by a restriction enzyme so that both strands are the same length. D. Sticky ends are DNA fragments that attract a carbohydrate molecule to one...
3. Restriction endonucleases cut DNA strands and leave either blunt or sticky ends. Describe the difference...
3. Restriction endonucleases cut DNA strands and leave either blunt or sticky ends. Describe the difference between these two types of ends.
1.When cloning a PCR product into a plasmid using restriction enzymes, the restriction enzyme recognition sequences...
1.When cloning a PCR product into a plasmid using restriction enzymes, the restriction enzyme recognition sequences in the PCR product most likely came from _______, and the restriction enzyme recognition sequences in the plasmid most likely came from ________. a. A multiple cloning site / the primers b. The primers / a multiple cloning site c. Both came from primers d. Both came from the multiple cloning site e. Naturally present in the gene of interest / the multiple cloning...
2. Here are some DNA fragments that have been isolated by gel electrophoresis after being cut...
2. Here are some DNA fragments that have been isolated by gel electrophoresis after being cut with restriction enzynes. A. 5 '-ACTGACATAGGCACCCCTTAA-3 3'-TGACTGTATCCGTGGGG-5 5 '-TGACTGTATCCGTGGGG-3' 3 '-ACTGACATAGGCACCCCTTAA-5' 5 '-GGCATACTAGATCCACGTTAA-3 3'-CCGTATGATCTAGGTGC-5 5 '-GGCATACTAGATCCACGAATT-3 3'-CCGTATGATCTAGGTGC-5 E. 5 '-GGCATACTAGATCCACGGATC-3 3'-CCGTATGATCTAGGTGC-5 a. Which pair of these fragments has appropriate complementary sticky ends to get joined together in a recombinant DNA molecule? b. What enzyme would we use to join up the DNA backbones to make the make the recombinant molecule?
You are performing an analysis of squirrel mitochondrial DNA, which is a circular double-stranded DNA molecule...
You are performing an analysis of squirrel mitochondrial DNA, which is a circular double-stranded DNA molecule that is 23,000 bp in length. You are using restriction enzymes and agarose gel electrophoresis in your experiments. You have decided to use two restriction endonucleases: Pstl and Tagl. The picture below shows their recognition sites, and the red arrows indicate their strand- Pstl (Providencia stuartii) CTGCAG GACGTC specific cleavage sites. Taqi (Thermus aquaticus) TCGA AGCT Part A: The Pstl and Taql enzymes both...
Question 1 1 pts Why is it important for DNA to have complementary base pairing? O...
Question 1 1 pts Why is it important for DNA to have complementary base pairing? O Complementary base pairing allows base pairs to be packed in the most energetically favorable arrangement inside of the double helix structure. O Complementary base pairing will pair a purine with a purine, which are a similar width, thus they are able to hold the sugar-phosphate backbone an equal distance apart along the DNA molecule o Complementary base pairing is only important for maintaining the...
Chromosomal and plasmid DNA can be cut into manageable pieces by restriction enzymes. Using agarose gel...
Chromosomal and plasmid DNA can be cut into manageable pieces by
restriction enzymes. Using agarose gel electrophoresis, the DNA
fragments can be separated on a gel, based on their lengths. In
order to see the fragments, a stain is typically added to the gel.
The size of each fragment can be determined by comparing each one
to a DNA molecular weight marker of known size.
Below is a map of pBR22 plasmid. The position and base pair
number of the...
Identify two restriction endonucleases that could be used to make sticky ends near the 5’ end of this DNA sequence (uppe...
Identify two restriction
endonucleases that could be used to make sticky ends near the
5’ end of this DNA sequence (upper strand) so that
it could be incorporated into a new plasmid. You have a short list
of them in Table 9-2, and the specific, short sequences of bases
that other enzymes cut at are easily obtained from web resources.
You must cut as near to the 5' end as possible. Indicate the
specific sequences of bases for each endonuclease...
Write true or false ______ 1. The DNA sequence of one human being is on average...
Write true or false ______ 1. The DNA sequence of one human being is on average 99.9% identical to another random human being. ______ 2. As of 2009, all living human beings have had their entire genome sequenced. ______ 3. The nucleotide bases present in a DNA sequence are A, U, G, C. ______ 4. Techniques that enabled scientists to clone genes were developed in the 1970s. ______ 5. A restriction enzyme is useful because it is a generic enzyme...
find the errors
Restriction enzymes recognize specific DNA sequences and cut each strand of DNA at specific locations at the target sequence. The result of digesting a particular genome with a particular restriction enzyme is a collection of restriction fragments of defined length and composition. These can be used to generate restriction maps or create pieces with sticky ends. These sticky ends can be used to attach to other fragments that have sticky ends caused by cutting with a different...
15- Which option BEST describes sticky ends by restriction enzymes B. Sticky ends A. Sticky ends are DNA fragments that carry a higher charge than normal after they have been cleaved are DNA fragments cleaved by a restriction enzyme so that one strand is longer than the other C. Sticky ends are DNA fragments cleaved by a restriction enzyme so that both strands are the same length. D. Sticky ends are DNA fragments that attract a carbohydrate molecule to one...
3. Restriction endonucleases cut DNA strands and leave either blunt or sticky ends. Describe the difference between these two types of ends.
2. Here are some DNA fragments that have been isolated by gel electrophoresis after being cut with restriction enzynes. A. 5 '-ACTGACATAGGCACCCCTTAA-3 3'-TGACTGTATCCGTGGGG-5 5 '-TGACTGTATCCGTGGGG-3' 3 '-ACTGACATAGGCACCCCTTAA-5' 5 '-GGCATACTAGATCCACGTTAA-3 3'-CCGTATGATCTAGGTGC-5 5 '-GGCATACTAGATCCACGAATT-3 3'-CCGTATGATCTAGGTGC-5 E. 5 '-GGCATACTAGATCCACGGATC-3 3'-CCGTATGATCTAGGTGC-5 a. Which pair of these fragments has appropriate complementary sticky ends to get joined together in a recombinant DNA molecule? b. What enzyme would we use to join up the DNA backbones to make the make the recombinant molecule?
You are performing an analysis of squirrel mitochondrial DNA, which is a circular double-stranded DNA molecule that is 23,000 bp in length. You are using restriction enzymes and agarose gel electrophoresis in your experiments. You have decided to use two restriction endonucleases: Pstl and Tagl. The picture below shows their recognition sites, and the red arrows indicate their strand- Pstl (Providencia stuartii) CTGCAG GACGTC specific cleavage sites. Taqi (Thermus aquaticus) TCGA AGCT Part A: The Pstl and Taql enzymes both...
Question 1 1 pts Why is it important for DNA to have complementary base pairing? O Complementary base pairing allows base pairs to be packed in the most energetically favorable arrangement inside of the double helix structure. O Complementary base pairing will pair a purine with a purine, which are a similar width, thus they are able to hold the sugar-phosphate backbone an equal distance apart along the DNA molecule o Complementary base pairing is only important for maintaining the...
Chromosomal and plasmid DNA can be cut into manageable pieces by
restriction enzymes. Using agarose gel electrophoresis, the DNA
fragments can be separated on a gel, based on their lengths. In
order to see the fragments, a stain is typically added to the gel.
The size of each fragment can be determined by comparing each one
to a DNA molecular weight marker of known size.
Below is a map of pBR22 plasmid. The position and base pair
number of the...
Identify two restriction
endonucleases that could be used to make sticky ends near the
5’ end of this DNA sequence (upper strand) so that
it could be incorporated into a new plasmid. You have a short list
of them in Table 9-2, and the specific, short sequences of bases
that other enzymes cut at are easily obtained from web resources.
You must cut as near to the 5' end as possible. Indicate the
specific sequences of bases for each endonuclease...
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