I need help on all parts Consider a power system shown in the figure has the...
Consider a 2-generator power system feeding a load through transmission network as shown in Figure below. The impedance data of the network is given in pu values on 100 MVA base. Using NR method find the bus voltages after two i terations. The scheduled power and nominal bus pu bus voltages are indicated in Figure below. Consider a 2-generator power system feeding a load through transmission network as shown in Figure 2. The impedance data of the network is given...
G 3. Draw the reactance diagram for the power system shown in Figure.3. The ratings of generator, motor and transformers are given below. Neglect resistance and use a base of 50 MVA, 138 kV in the 40 Ohms Line :20MVA, 18 kV, X = 20% :20MVA, 18 kV, X = 20% Synchronous Motor: 30MVA 13.8Kv X = 20% 3-phase, Star-Star Transformer: 20 MVA, 138/20 kV, X= 10% 3-phase, Star-Delta Transformer: 20 MVA, 138/20 kV, X = 10% G2 y j4012...
PLEASE COMPLETE ALL PARTS AND SHOW ALL WORK. 6. Consider the system shown below. The generator initially supplies 10 MW at unity power factor to the infinite bus. The voltage atthe infinite bus has a magnitude of 1 pu. Note that there is no load at bus 4 L1 G 1 D2 G1 20 kV 20 MVA 3 phase 60 Hz 4 pole X' 0.15 pu H 5 S T 20 kV Y- 169 kV Y 20 MVA 3 phase...
Please show all the clearly step Y11 ist j30 and Y44 isnt -j12.85 Consider the 4-bus power system shown in Fig. 1. The system parameters are given below: 50 MVA, 20 kV, X-2090 40 MVA, 20 kV, X-20%, X, = 5% 50 MVA, 20 kV Δ /110 kV Ý, X= 1090 50 MVA, 20 kV MI 10 kV Ý, X= 10% Xi-24.2 Ω Generator G: Motor M: Transformer T1 : Transformer T2 : Transmission line: 3 4 T2 nu)M Fig....
The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below T2 2 Line Vm G M 1 BA Figure 2 One-line diagram for problem 2 G: Ti: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose 20 kV as...
2 - The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. Ti T2 VA Line 2 G M Vm BE BE Figure 2 One-line diagram for problem 2 G: T: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base....
The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. T1 T2 V. 1 2 vm 9 Line G M Figure 2 One-line diagram for problem 2 G: T1: 60 MVA 50 MVA 50 MVA T2: Line: M: 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j200 12 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose...
Consider the single-line diagram of the three-phase power system shown in Figure 1. Component ratings are as follows: Generator G1: 750 MVA, 18 kV, X0.2 per unit Generator G2: 750 MVA, 18 kV, X 0.2 per unit Synchronous Motor M: 1,500 MVA, 20 kV, X-20% A-Y Transformers Ti, T2, T's, & T.: 750 MVA, 500 kV Y/20 kV A, X = 10% Y-Y Transformer T's 1,500 MVA, 500 kV Y/20 kV Y, X-10% ne L:X (a) Using bases of 100...
1. The one-line diagram of a three-pha se power system is shown in Figure 3.29. Select a common base of 100 MVA and 15 kV on the motor side. Draw an impedance diagram with all impedances including the load impedance marked in per-unit. The manufacturer's data for each device is given as follow:The three-phase load at bus 4 absorbs 57 MVA, 0.6 power factor lagging at 10.45 kV. Line 1 and line 2 have reactances of 48.4 Ω and 65.43...
Question 4 The power system shown is supplying a balanced wye-grounded resistive load that consumes the MW at 1.1 kV. An SLG fault occurs at bus 3. Determine the fault current and the voltages at the fault point. Assume that the fault resistance is 6.6 2. The equipment parameters are shown in the figure. 3 4 2 (1 (1 + j5) 2 10 MW Tuto 20 MVA 22/1.1 kV X = X2 = Xo = 0.05 pu Generator 30 MVA...