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ransformer TZXı = Χ, = 0.10 pu, X,-00 Transformer T, x,-X,-Xo = 0.50 pu Transformer Tl: x, = x, = 0.30 pu, X.-0。 Transmission


(d) If neutral Is 27. Consider th e system shown in Figure P5.3. Assume that the following data are given based on 20 MVA and
ransformer TZXı = Χ, = 0.10 pu, X,-00 Transformer T, x,-X,-Xo = 0.50 pu Transformer Tl: x, = x, = 0.30 pu, X.-0。 Transmission line TL23-X-X2 = 0.15 pu, Xo = 0.50 pu Transmission line TL35: X1-X2 = 0.30 pu, Xo = 1.00 pu Transmission line TL57: Xi = X2 = 0.30 pu, X,-1.00 pu Draw the corresponding positive-sequence network Draw the corresponding negative-sequence network Draw the corresponding zero-sequence network (e) (b) (c) Ti TL23 T2 18.75 MVA 1 △Y1 1345/13.8 kv 15 MVA 13.8/34.5 kV 20 MVA TL3s T3 T4 TLS7 5 MVA 34.5/2.4 kv 3 MVA 2.4/34.5 kV 5 MVA FIGURE P5.3 System for Problem 27
(d) If neutral Is 27. Consider th e system shown in Figure P5.3. Assume that the following data are given based on 20 MVA and the line-to-line base voltages as shown in Figure P5.3. Generator Gi-x, = 0.25 pu, X,-0.15 pu, X。= 0.05 pu Generator G2:X2= 0.90 pu, X2 = 0.60 pu, XO = 0.05 pu Transformer Tl: x, x, x, 0.10 pu
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Answer #1

Transmission line TL a3之 Xi= X2 。·15 メa=0.50 Ru o un01 Sihve seqcence, Nehoork! L23 S 0.9375 p TL35 Ta TL 3:33 pn 3. 6 pu, Х,20:30, , Power Source (9 ve Se4encf T2. TL23 13P니 .zero seqence ル23 5 e. 053 open circui+ 12, 1.o JL3s しne 7 3 14- 2. 3.33 p,n r 57 O C

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