The strains and markers are as per the solution is as given below:
STRAINS | MARKERS | ||||
1 | M | Z | X | W | C |
2 | L | A | N | C | W |
3 | A | L | B | R | U |
4 | Z | M | U | R | B |
There are four strains with four different markers for each. In total, there are four strains with sixteen markers.
The problem is analogous in forming long gene maps with a series of three-point testcrosses. When the four sequences are arranged, they overlap and form the regions in given aligned series:
The regions with the bars above or below are identical in sequence. They are close to circular chromosome. The correct order of these markers on the circular chromosome of the original F+ is,